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zysi [14]
2 years ago
13

Which algebraic expression is a polynomial? Which term could be put in the blank to create a fully simplified polynomial written

in standard form? 8x3y2−_____+3xy2−4y3 x2y2 x3y 7xy2 7x0y3
Mathematics
2 answers:
kifflom [539]2 years ago
7 0

Answer:

x^3y and  x^2y^2

Step-by-step explanation:

An algebraic expression is a polynomial if and only if the variables involve have positive integral indices or exponents.

The given polynomial is: 8x^3y^2----------+3xy^2

We want to put one of the following polynomials in the blank space to create a fully simplified polynomial written in standard form.

-4y^3

x^2y^2

x^3y

7x^2y

7x^0y^3

A fully simplified polynomial written in standard form is obtained by writing the simplified polynomial in decreasing order according to degree.

Since the first term of  8x^3y^2----------+3xy^2 having a degree of 5 and the last term is having a degree of 3.

The polynomial that goes into the blank must have a degree of 4.

This eliminates -4y^3, 7x^2y

and 7x^0y^3

We are now left with x^2y^2 and x^3y

The required polynomial is therefore 8x^3y^2-x^2y^2+3xy^2 or8x^3y^2-x^3y+3xy^2

These two polynomials are in standard form and cannot be simplified further.

The correct choices are;

x^3y and  x^2y^2

Diano4ka-milaya [45]2 years ago
3 0

Answer:x2y2

Step-by-step explanation:

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0.5×- 1.2 =0.4× + 3.3​
Dennis_Churaev [7]

Answer:

0.02

Step-by-step explanation:

0.5 x - 1.2 = 0.4x + 3.3

0.1x = 4.5

x = 0.02

Hope that helps!

3 0
2 years ago
The wildlife department has been feeding a special food to rainbow trout fingerlings in a pond. based on a large number of obser
Liono4ka [1.6K]
The normal distribution curve for the problem is shown below

We need to standardise the value X=405.5 by using the formula

z-score= \frac{X-Mean}{Standard Deviation}
z-score= \frac{405.5-402.7}{8.8} =0.32

We now need to find the probability of z=0.32 by reading the z-table

Note that z-table would give the reading to the left of z-score, so if your aim is to work out the area to the right of a z-score, then you'd need to do:

P(Z\ \textgreater \ z)=1 - P(Z\ \textless \ z)

from  the z-table, the reading P(Z\ \textless \ 0.32) gives 0.6255

hence, 
P(Z\ \textgreater \ 0.32)=1-0.6255=0.3475

The probability that the mean weight for a sample of 40 trout exceeds 405.5 gram is 0.3475 = 34.75%

7 0
2 years ago
Please help please.......​
faust18 [17]
1. 34.8 2. 127.2 the other ones
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hodyreva [135]

Refer the attachment for your answer :)

4 0
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The Tennis Club decided to buy T-shirts for its members. Action Sports Apparel quoted the following prices for the T-shirts.
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Step-by-step explanation:

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