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OverLord2011 [107]
3 years ago
10

Ricardo transformed the quadratic parent

Mathematics
1 answer:
Umnica [9.8K]3 years ago
7 0
It will B just did a similar question like that
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What is 5/5 in simplest form?
Mama L [17]
Hello!
 
5/5 in simplest form equals 1

5 divided by 5 is 1
8 0
3 years ago
Read 2 more answers
9, 2.5, –4, –10.5, –17, .
Vedmedyk [2.9K]
What do you mean? If you want it in order than you can say it. -17, -10.5, -4, 2.5, 9
7 0
4 years ago
Please help me with this
Vera_Pavlovna [14]

Answer:

226.19

Step-by-step explanation:

pi * r^2 = area

The radius = diameter/2 = 6

pi * 6^2 * 2 = area of 2 tortillas

72pi = area of 2 tortillas

That rounds to 226.19

3 0
4 years ago
Help plese.........ooj
Tatiana [17]
The answer is 6. You can find slope by using the slope formula: M= y1 - y2 / x1 - x2. In this case you can choose any two points from the table. I chose the second two points. the equation would then be (7-1) / (2-1). It would then be 6/1 or 6.
Hope this helped(:
3 0
3 years ago
Hi guys, can anyone help me with this triple integral? Many thanks:)
Crank

Another triple integral.  We're integrating over the interior of the sphere

x^2+y^2+z^2=2^2

Let's do the outer integral over z.   z stays within the sphere so it goes from -2 to 2.

For the middle integral we have

y^2=4-x^2-z^2

x is the inner integral so at this point we conservatively say its zero.  That means y goes from -\sqrt{4-z^2} and +\sqrt{4-z^2}

Similarly the inner integral x goes between \pm-\sqrt{4-y^2-z^2}

So we rewrite the integral

\displaystyle \int_{-2}^{2} \int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}} \int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dx \; dy \; dz

Let's work on the inner one,

\displaystyle\int_{-\sqrt{4-y^2-z^2}}^{\sqrt{4-y^2-z^2}} (x^2+xy+y^2)dz

There's no z in the integrand, so we treat it as a constant.

=(x^2+xy+y^2)z \bigg|_{z=-\sqrt{4-y^2-z^2}}^{z=\sqrt{4-y^2-z^2}}

So the middle integral is

\displaystyle\int_{-\sqrt{4-z^2}}^{\sqrt{4-z^2}}2(x^2+xy+y^2)\sqrt{4-y^2-z^2} \ dy  

I gotta go so I'll stop here, sorry.

7 0
3 years ago
Read 2 more answers
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