Answer:
perimeter-
perimeter outer rectangle = 2 (l+b)
=2×8+9
= 2×17
2×17 =34 cm sq.
perimeter of inner rectangle = 2 (l+b)
= 2×5+3
=2× 8
= 16 cm sq.
perimeter of shaded portion= 34 - 16
= 18 cm sq.
area-
<em>area</em><em> </em><em>of</em><em> </em><em> </em><em>inner</em><em> </em> rectangle =l×b
l×b = 3×5
3×5=15
15 cm sq.
area of outer rectangle =l×b
l×b= 9×8
9×8= 72
72 cm sq.
area of shaded portion = 72 -15 =57 cm sq.
hey there! In second method i have done first area of inner rectangle but you have to do first area of outer rectangle...
hope it helps you....
20: 30-4 x (2+5)=2
21. 17-(8-5)= 14
22. You put (10/2)-3+1, but it isn't necessary
Explanation: to solve these equations, use PEMDAS (parentheses, exponents, multiplication, division.) these equations don't involve exponents, though, so ignore that part. If 30 is left alone, you would multiply 4x2 before doing anything else. This would mean you would have 30-8+5' which gets you to 27, an incorrect answer. However, if you put parentheses around (2+5), you add those first, meaning you would then have 30-4(2+5) = 30-4(7) = 30-28= 2.
Try to do the rest; if you're still having trouble add a comment
Y intercept occurs when x = o so it is -2(0-3) + 4 = -2
x intercepts:-
-2(x - 3)^2 + 4 = 0
(x - 3)^2 = -4/-2 = 2
x - 3 = +/- sqrt2
x = 3 + sqrt2 and 3- sqrt2
We are given a circle graph that shows the time spent on homework last week.
Jacob spent a total of 16 hours doing homework.
The time spent on doing science homework is given by
The time spent on doing band practice is given by
The difference between the time spent on science homework and band practice is
Therefore, Jacob spent 2 more hours on science homework than band practice.
Asymmetrical
its not symmetrical because symmetrical means that they’re the exact same with those two lines obviously aren’t
high is obviously just one of those idiot answer choices thrown in to see if you’ll be aa smart alec and choose that so it’s obviously not that
which leave you with c. asymmetrical
