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NeX [460]
3 years ago
13

Can you help please on this question i am stuck

Mathematics
2 answers:
Luba_88 [7]3 years ago
6 0
You got to skip that question it’s a college question
zhuklara [117]3 years ago
3 0
The answer would be 360 :) do you have to show working?
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1/2x+5=1/3x what do you multiply the equation by in order to get rid of the fractions in the problem
earnstyle [38]

Answer:

we should multiply by 6 to get rid of the fractions in problem

6 0
2 years ago
How many parallelograms are in an octagonal prism?
Snezhnost [94]

Answer:

In this way, two hexagons and a parallelogram with five inner lines are obtained. Each hexagon has six edges, therefore the prism will have more than 12 edges. At first glance, it is thought that the parallelogram contains nine edges (seven vertical and two horizontal).

6 0
2 years ago
Find the circumference to the nearest tenth
gregori [183]
C=3.14(15.6)
C=48.9-> 49 
4 0
3 years ago
Differentiate. F(x) = (x3 - 3)2/3 2x f'(x) - 3 8 O f'(x) = 3 8 2x2 f'(x) 3 VX3 -8 f(x) 3 V3-8​
oee [108]

Answer:

f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } }

Step-by-step explanation:

f(x) = ( {x}^{3}  - 8)^{ \frac{2}{3} }  \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2}{3} - 1 } (3 {x}^{2}  - 0) \\  \\ f'(x) =  \frac{2}{3} ( {x}^{3}  - 8)^{ \frac{2 - 3}{3}  }  \times 3 {x}^{2} \\  \\ f'(x) =  2{x}^{2}( {x}^{3}  - 8)^{ \frac{ - 1}{3}  } \\  \\ f'(x) =   \frac{2{x}^{2}}{( {x}^{3}  - 8)^{ \frac{ 1}{3}  } } \\  \\ \huge \red{ \boxed{ f'(x) =   \frac{2{x}^{2}}{ \sqrt[3]{( {x}^{3}  - 8) } } }}

3 0
3 years ago
ILL MARK BRAINLIEST.
Alexxx [7]

Answer:

c

Step-by-step explanation:

c because you would get fals as the answer because to solve you first distribute so you would get 3x+7=3x+6 and both 3 x's would cancel out so you would get 7=6 so that would be false

4 0
3 years ago
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