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Vikki [24]
2 years ago
7

What is 6,539.63 rounded to the nearest whole number

Mathematics
2 answers:
grandymaker [24]2 years ago
5 0
Nearest whole number is without decimals. 6540 is the nearest whole number.
vovangra [49]2 years ago
3 0
6540 is the answer

Rate and thanks!
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ozzi
Say what now I hadn’t learned that yet omg I’m sry
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2 years ago
The mathematics department of a college has 10 male​ professors, 12 female​ professors, 12 male teaching​ assistants, and 15 fem
lana [24]

We need the total count of persons = 10+12+12+15 = 49 persons

We need the count of the target group, female or teaching assistants

= (10+12) professors + 12 male teaching assistants

= 22+12

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Assuming equal probability of choosing anyone from the 30 persons, the

probability of choosing a professor or a male

= 34/49

(For probability calculations, try to keep a fraction for as long as you can, because fractions are exact. Decimal are frequently approximate, for example in this case, 34/49=0.693877551020...... = 0.694 approximately)

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zhuklara [117]
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3 years ago
How do you find the area of this (it is not 12 or 18) The First answer gets brainliest
bija089 [108]

Answer:

<em><u>ok the area of a trapezoid is 48 </u></em>

a+b divided by two multiplied by height  

Step-by-step explanation:

each square equals 2 so you count by twos instead of ones..

the height is 8   the base is 8 and the top is 4 so

4+8/2=6

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6 0
3 years ago
If f(x)=2x^2+(1000/x), find the average rate of change of f(x) from x=a to x=a+h.
galina1969 [7]

Answer:

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Step-by-step explanation:

average rate of change is

\frac{f(a+h)-f(a)}{a+h-a}, by slope formula

simplify this to get \frac{f(a+h)-f(a)}{h}, which is the definition of the derivative as h goes to 0

\lim_{h \to 0} \frac{f(a+h)-f(a)}{h}

since you defined x=a, we can substitute a for x and vice versa to find our derivative.

\lim_{h \to 0} \frac{(2x^2+\frac{1000}{x+h})-(2x^2+\frac{1000}{x})}{h}

simplifying

\lim_{h \to 0} \frac{\frac{1000}{x+h}-\frac{1000}{x}}{h} (your average rate of change)

6 0
2 years ago
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