Answer:
(A) Yes, x = 2 is a zero of the polynomial.
The quotient is x² + 26x + 160 and the remainder is 0
Step-by-step explanation:
Given;
p(x) = x³ + 24x² + 108x - 320
Using remainder theorem to test if x = 2 is a zero of the given function
p(2) = (2)³ + 24(2)² + 108(2) - 320
= 8 + 96 + 216 - 320
= 0
Thus, x = 2 is zero of the function
(ii) to get the quotient and the remainder of the given function, divide the function by 'x - 2'
x² + 26x + 160
x - 2 √ x³ + 24x² + 108x - 320
- (x³ - 2x²)
0 + 26x² + 108x - 320
- (26x² - 52x)
0 + 160x - 320
- (160x - 320)
0 + 0
The quotient is x² + 26x + 160
The remainder is 0
Thus, the correct option is A.
Yes, x = 2 is a zero of the polynomial.
The quotient is x² + 26x + 160 and the remainder is 0
