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vovangra [49]
4 years ago
6

How is periodicity of properties dependent upon number of protons in an atom?

Physics
2 answers:
LUCKY_DIMON [66]4 years ago
4 0
It's because of the charge
netineya [11]4 years ago
3 0
Depending on the charge.
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Which light waves travel faster radio waves or gamma waves?
qaws [65]

Answer:

In a vacuum all light travels the same speed no matter what the wavelength or frequency. Gamma radiation has a smaller wavelength and larger frequency, radio waves a smaller frequency and larger wavelength.

Explanation:

3 0
3 years ago
If a ball is rolled down a frictionless inclined plane from a height of 3 feet, to what height would it roll up to on the other
mojhsa [17]

Answer:

It will roll up to its initial height from which it rolled from on the first hill

Explanation:

The given information are;

The height from which the ball is rolled = 3 feet[

The equation of the potential energy of the ball as it rolled down the frictionless inclined plane is given by the following equation;

m × g × h₁ = 1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r]

Where;

m = The mass of the ball

h = The from which the ball is rolled down

v = The velocity of the ball

r = The radius of the ball

Therefore, all the potential energy, m × g × h, is converted into kinetic energy when the ball reached the ground

Similarly, as the ball rolls up on the other side, by the principle of energy conservation, all the kinetic energy is transformed into potential energy as follows

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₂, therefore, we have;

1/2 × m × v² + 1/2×[2/5× m × r²) × [v/r] = m × g × h₁ =  m × g × h₂

Therefore since m × g × h₁ =  m × g × h₂, then h₁ = h₂, the ball rises to the same height it started rolling from on the first hill.

3 0
3 years ago
What are cognitive changes that occur during
horrorfan [7]

Answer:A C E

Explanation:

4 0
3 years ago
What is the main function of chloroplasts?
dangina [55]

Answer:

C

To convert sunlight into usable sugars

(

Explanation:

6 0
4 years ago
Three identical particles, q1, q2, and q3, each with charge q = 5.00 μC, are placed along a circle of radius r = 2.00 m at angle
wariber [46]

Answer:

11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

Explanation:

q = magnitude of charge on each particle = 5 μC =  5 x 10⁻⁶ C

r = distance of each particle from center of circle = 2 m

E = Magnitude of electric field at the center by each particle

Magnitude of electric field at the center by each particle is given as

E = \frac{kq}{r^{2} }

inserting the values

E = \frac{(9\times10^{9} )(5\times10^{-6})}{2^{2} }\\E = 11.25\times10^{3} NC^{-1}

From the diagram , we see that being equal and opposite, the electric fields due to charge q₁ and q₃ cancel out.

So net electric field at center is only due to charge q₂ direction towards positive x-direction

So

E_{res} = Resultant electric field = 11250 N/C

Direction: 0 deg counterclockwise from positive x-axis

7 0
3 years ago
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