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Artemon [7]
3 years ago
5

What are cognitive changes that occur during

Physics
1 answer:
horrorfan [7]3 years ago
4 0

Answer:A C E

Explanation:

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If an R = 1-kΩ resistor, a C = 1-μF capacitor, and an L = 0.2-H inductor are connected in series with a V = 150 sin (377t) volts
fgiga [73]

Answer

given,

R = 1-kΩ  = 1000 Ω

C = 1-μF

L = 0.2-H

V = V_max sin( ω t)

comparing

V = 150 sin ( 377 t)

ω = 377

\chi_c = \dfrac{1}{\omega C}

\chi_c = \dfrac{1}{377 \times 1 \times 10^{-6}}

\chi_c = 2652.5\Omega

\chi_L =377 \times 0.2

\chi_L =75.4\ \Omega

Impedance,

Z = \sqrt{R^2+(\chi_L-\chi_c)^2}

Z = \sqrt{1000^2+(75.4 -2652.5)^2}

Z = 2764.3 Ω

now,

V_{max} = 150 V

I_{max} = \dfrac{V}{Z}

I_{max} = \dfrac{150}{2764.3}

I_{max} = 0.0543

I_{max} = 54.3\ mA

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3 years ago
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Answer:

17

Explanation:

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3 years ago
If we have 300 centimeters,we would have
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3 meters................
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What force is required to balance the wheelbarrow if the load is 600N, load distance is 20cm, effort distance is 80cm?​
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3 years ago
Calculate the equivalent resistance for both circuits.
Allisa [31]

Answer:

Series equivalent resistance: R_{eq} = 6  \Omega

Parallel equivalent resistance: R_{eq}=14\Omega

Explanation:

The equivalent resistance in series circuit is calculated as

R_{eq} = R_{1} + R_{2}

R_{eq} = 2 + 4

R_{eq} = 6  \Omega

The equivalent resistance in parallel circuit is calculated as

\frac{1}{R_{eq}} = \frac{1}{R_{1}}+\frac{1}{R_{2}}

Which can be simplified to

R_{eq}=\frac{R_{1}\times R_{2}}{R_{1}+R_{2}}

R_{eq}=\frac{21\times 42}{21+42}

R_{eq}=14\Omega

The parallel circuit has the higher equivalent resistance as compared to series circuit.

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