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RSB [31]
2 years ago
12

teacher has 27 students in her class she asked the students to form as many groups of 4 as possible how many students are not be

in a group
Mathematics
1 answer:
stepan [7]2 years ago
4 0
If there are 27 students in the class and they have to form as many groups of 4 as possible, you can calculate this using the following step: 

27 / 4 = 6.75 = 6 3/4

Result: 27 students can form 6 groups of 4 students and 3 students have to form their own group.
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Sabra joins a cooking club for $8.50 and pays $6.25 each month. She also joins a movie club for $12 and pays $3.75 each month. W
podryga [215]

Simplified expression for total amount spent is 10(2.05 + m)

Step-by-step explanation:

  • Step 1: Write expression for expense on joining cooking club for m months.

Expense = 8.50 + 6.25 × m

  • Step 2: Write expression for expense on joining movie club for m months.

Expense = 12 + 3.75 × m

  • Step 3: Calculate the total amount spent on both clubs

Total Amount = 8.50 + 6.25m + 12 + 3.75m = 20.5 + 10m = 10(2.05 + m)

6 0
3 years ago
7x + 8y = 25 9x + 10y =35 elimination method please​
djverab [1.8K]

7x +8y = 25 ~~~....(i)\\\\9x +10y = 35~~~ ....(ii)\\\\\text{Multiply equation (ii) by}~ \dfrac 79 ~ \text{and do (ii) - (i):}\\\\\dfrac 79 (9x +10y) - (7x +8y) = \dfrac 79 (35) - 25\\\\\\\implies 7x +\dfrac{70y}9 - 7x -8y = \dfrac{245}9 -25\\\\\\\implies - \dfrac{2y}9 =  \dfrac{20}9\\\\\\\implies -2y =20\\\\\implies y =-10\\\\\text{Substitute}~ y = -10~ \text{in equation (i):}\\\\\\7x +8(-10) = 25\\\\\implies 7x  = 25 +80\\\\\implies 7x = 105 \\\\\implies x =15\\\\

\\\text{Hence}~ (x,y) = (15,-10)

3 0
2 years ago
Write an algebraic expression from the following
gavmur [86]

A: (x^2) + 2x

B: (3x)/(4+x)

C: (5-x) × 3x

4 0
3 years ago
Which of the following numbers is not written in scientific notation?
Sonja [21]

Answer A

Step-by-step explanation:

Because there is a zero at the begining.

8 0
2 years ago
Is the sqrt of -36 a real number
Mkey [24]

Answer:

No

Step-by-step explanation:

The square root of any negative number is not a real number.

4 0
3 years ago
Read 2 more answers
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