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Sliva [168]
3 years ago
10

-2 ( 6 + 7n ) = 3n + 5

Mathematics
1 answer:
jek_recluse [69]3 years ago
7 0

Answer:

n = -1

Explanation:

First we need to distribute the -2 throughout the variable getting us to

-12 - 14n = 3n + 5

Then we need to move the variable n to one side and isolate it. To do this, subtract 3n from both sides and add 12 to both sides.

-17n = 17

Now, we need to remove the co-efficient from n, so we need to divide both side by -17.

n = -1

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What do u do when the question says what is an area of the rectangle Like
Anastaziya [24]

Answer:

multiply

Step-by-step explanation:

Area is measured in square units such as square inches, square feet or square meters. To find the area of a rectangle, multiply the length by the width.

6 0
3 years ago
X squared plus 8X +12
Xelga [282]

Answer:

(x+2)(x+6)

Step-by-step explanation:

x2 + 8x +12

x              2

x              6

5 0
3 years ago
Use Newton's method with initial approximation x1 = 1 to find x2, the second approximation to the root of the equation x4 − x −
drek231 [11]

Answer:

x_{2} = 0.0000

Step-by-step explanation:

The formula for the Newton's method is:

x_{i+1} = x_{i} + \frac{f(x_{i})}{f'(x_{i})}

Where f' (x_{i}) is the first derivative of the function evaluated in x_{i}.

x_{i+1} = x_{i} + \frac{x_{i}^{4}-x_{i}-3}{4\cdot x_{i}^{3}-1}

Lastly, the value of x_{2} is determined by replacing x_{1} with its numerical value:

x_{2} = x_{1} + \frac{x_{1}^{4}-x_{1}-3}{4\cdot x_{1}^{3}-1}

x_{2} = 1.0000 + \frac{1.0000^{4}-1.0000-3}{4\cdot (1.0000)^{3}-1}

x_{2} = 0.0000

8 0
3 years ago
The heights of women aged 20 to 29 are approximately normal with mean 64 inches and standard deviation 2.7 inches. Men the same
san4es73 [151]

Answer:

Step-by-step explanation:

Z=\frac{x-mu}{\sigma }

X - Heights of women aged 20 to 29: X is N(64, 2.7)

Y - Heights of men aged 20 to 29: X is N(69.3, 2.8)

a) X=6'=72"

Z=\frac{72-64}{2.7} =2.963

b) Y = 72"

z=\frac{72-69.3}{2.8} =0.965

c) 72' women can be taken as very tall but men moderately taller than average

d) Y<5'5" =65"

Z<\frac{65-69.3}{2.8} =-1.536

e) X>73"

Z>\frac{73-64}{2.7} =3.33

Almost 0% can be taken

f) IQR =Q3-Q1

Z scores =

5 0
4 years ago
A vehicle arriving at an intersection can turn right, turn left, or continue straight ahead. The experiment consists of observin
Temka [501]

Answer:

a) Sample space (S) = {TR, TL, Cs}

b) Pr(Vehicle Turns) = 2/3.

Step-by-step explanation:

a) By sample space (S) we mean the list all possible outcome of an event. From the illustration in the question, only three (3) outcome is possible:

i) Vehicle Turn Right (TR)

ii) Vehicle Turn Left (TL)

iii) Continue Straight ahead (Cs)

And since the experiment consists of observing the movement of a single vehicle through the intersection, then, the sample space (S) is:

==> {TR, TL, Cs}

b) Since we are assuming that all sample points are equally likely, it imply that they have equal probability of occurring. And by probability:

Pr(TR) = 1/3

Pr(TL) = 1/3

Pr(Cs) = 1/3

Meanwhile, the question wants us to find the probability that the vehicle turns. This means, the vehicle turning either right or left. Thus;

Pr(vehicle turns) = Pr(TR) or Pr(TL) = Pr(TR) + Pr(TL)

Pr(vehicle turns) = (1/3) + (1/3) = 2/3

4 0
3 years ago
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