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ratelena [41]
3 years ago
7

A piece of tile is 4 1/2 inches long and 3 1/4 inches wide. What is the area of the tile? A.7 3/4 B.12 C.12 1/8 D.14 5/8

Mathematics
1 answer:
Komok [63]3 years ago
7 0

4 x 2 over 2

8/2 + 1/2 = 9/2

3 x 4 over 4

12/4 +1/4 = 13/4

Top times top over bottom times bottom.

9 x 13 over 2 x 4

117 / 8

14 and 5/8


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Titus had 1/2 can of paint. He used 2/3 to paint a tabletop. What fraction of a full can of paint did Titus use?
dimaraw [331]
I think its 1 1/6 idk
7 0
3 years ago
The lateral area of a cone is 400 pi cm squared. The radius is 10 cm. Find the slant height to the nearest tenth.
Ilia_Sergeevich [38]

Answer:

Option A. 40\ cm

Step-by-step explanation:

we know that

The lateral area of a cone is equal to

LA=\pi rl

we have

LA=400\pi \ cm^{2}

r=10\ cm

substitute and solve for l (slant height)

400\pi=\pi (10)l

simplify

400=(10)l

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8 0
3 years ago
Which ordered pair is the solution to the system of equation
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3 0
3 years ago
How much bigger is the Sum of first 50 even numbers than the sum of first 50 odd numbers?
Lunna [17]

Answer:

50

Step-by-step explanation:

Sum Even numbers

n = 50

d = 2

a1 = 2

The last number is

an = a1 + (n-1)d

an = 2 + (50 - 1)*2

an = 2 + 49 * 2

an = 2 + 98

an = 100

Sum of the even numbers

Sum = (a1 + a50)*n/ 2

Sum = (2 + 100)*50/2

sum = 102 * 25

sum = 2550

Sum of the first 50 odd numbers

a1 = 1

n = 50

d = 2

l = ?

Find l

l = a1 + (n - 1)*2

l = 1 + 49*2

l = 99

Sum

Sum = (1 + 99)*50/2

Sum = 2500

The difference and answer is 2550 - 2500  = 50

7 0
3 years ago
23 + 4 + x = 25 -12 porfa ayuda :(
MAXImum [283]

Answer:

x = - 14

Step-by-step explanation:

23 + 4 + x = 25 - 12

Combine like terms on both sides of the equation (by adding 23 and 4 on the left-hand side, and subtracting 12 from 25 on the right-hand side):

23 + 4 + x = 25 - 12

27 + x = 13

Next, subtract 27 from both sides to solve for x:

27 - 27 + x = 13 - 27

x = - 14

Please mark my answers as the Brainliest if you find this explanation helpful :)

4 0
3 years ago
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