Find the value of sec θ for the angle shown

Mathematics

1 answer:

amm18123 years ago

4 0

$\bf (\stackrel{\stackrel{x}{adjacent}}{7}~~,~~\stackrel{\stackrel{y}{opposite}}{6})\impliedby \textit{let's find the \underline{hypotenuse}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies c=\sqrt{a^2+b^2}\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
c=\sqrt{7^2+6^2}\implies c=\sqrt{85}\\\\
-------------------------------\\\\
sec(\theta)=\cfrac{hypotenuse}{adjacent}\qquad \qquad sec(\theta)=\cfrac{\sqrt{85}}{7}$

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