To get the coordinates of C we shall proceed as follows:
AB:BC=1:4
B-A=[(-3--7),(-5--8)]=(4,3)
4(4,3)=(16,12)
thus the coordinates of C will be:
(16-3,-5+12)
=(13,7)
Answer:
4
Step-by-step explanation:
On a number line you will got to -8 and go up 12 and you would get 4
The standard form of the equation of a circle of radius r, with (assuming centre h, k) is given as:
(X-h)^2 + (y-k)^2 = r^2
As we are required to write an equation in standard form for the circle with radius 9 centred at the origin.
Centre(h,k)=(0,0), r=9
Substituting these values into the standard form of the equation of a circle given above:
(X-0)^2 + (y-0)^2 = 9^2
X^2 + y^2 =81
The standard form is x^2 + y^2 =81
I’m pretty sure this is right
