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sergiy2304 [10]
3 years ago
5

Identify whether the given numbers are perfect squares, perfect cubes, or neither.

Mathematics
1 answer:
Anna [14]3 years ago
5 0
8- perfect cube. 2×2×2=8
9-perfect square. 3×3=9
21- neither.
27- perfect cube. 3×3×3=27
1331- perfect cube. 11×11×11=1331
1332- neither
100- perfect square. 10×10=100
1000- perfect cube. 10×10×10=1000
126- neither
125- perfect cube. 5×5×5=125
25-perfect square. 5×5=25
81-perfect square. 9×9=81
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Which is another way to check the sum of 104+34+228+877?
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The answer is digit sum method.

Digit sum method is method used to check the sum of sum numbers. If the sum of all of the digits of numbers is equal to the sum of all of the digits of the total sum, then the arithmetic process was correct.

We need to check the sum of <span>104+34+228+877:
</span>104 + 34 + 228 + 877 = 1243

Let's first summarize the digits of individual numbers:
104 *** 1 + 0 + 4 = 5
34 *** 3 + 4 = 7
228 *** 2 + 2 + 8 = 12 *** 1 + 2 = 3
877 *** 8 + 7 + 7 = 22 *** 2 + 2 = 4

Now, let's sum these sums:
5 + 7 + 3 + 4 = 19 *** 1 + 9 = 10 *** 1 + 0 = <u><em>1</em></u>

Then, let's summarize the digits of the total sum:
1243 *** 1 + 2 + 4 + 3 = 10 *** 1 + 0 = <u><em>1</em></u>

Since the sums of the digits on the both sides of equation is 1, than the arithmetic process was correct and the sum of <span>104 + 34 + 228 + 877 is really 1243.</span>

7 0
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