Solve |x - 1|>4 a. {x|x< -5 or x> 5} b. {x|-3< x< 5} c. {x|x< -3 or x> 5}
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Answer:
<em>f</em> has no critical points.
Step-by-step explanation:
We are given:
A function has critical points whenever its derivative equals 0 or is undefined.
Differentiate the function:
Since this will never be undefined, solve for its zeros:
Hence:
Recall that the value of sine is always between -1 and 1.
Thus, no real solutions exist.
Therefore, <em>f</em> has no critical points.