Answer:
The child has 6 dimes and 5 quarters.
Step-by-step explanation:
Let q and d represent the number of quarters and of dimes respectively.
Then q + d = 11 (Equation A), and ($0.25/quarter)q + ($0.10/dime)d = $1.85 (Equation B).
Multiply the 2nd equation by 100 to remove the decimal fractions:
25q + 10d = 185 (Equation C)
Now multiply the 1st equation by -10 to obtain -10q - 10d = -110 (Equation D), and combine this result with Equation C:
-10q - 10d = -110
25q + 10d = 185
--------------------------
15q = 75, and so q = 75/15 = 5.
According to Equation A, q + d = 11. Replacing q with 5, we get:
5 + d = 11, and so d = 6.
The child has 6 dimes and 5 quarters.
Let us say that:
x = hours worked by Wolfgang
y = hours worked by Heinrich
So that:
x = y + 10
14 x + 12 y = 3520
By combining the two equations:
14 (y + 10) + 12 y = 3520
14 y + 140 + 12 y = 3520
26 y = 3380
y = 130 hours
x = y + 10 = 140 hours
<span>So Wolfgang worked 140 hours while Heinrich worked 130
hours.</span>
Answer:
here you go. hope this helps
It will take Marvin 12 days to exersise for 576
If the game will start at 11:00 A.M., but the players must arrive at the field three-quarters of an hour early to warm up, it refers to 8:45 a.m. Why? If we start to count in 11 backward and start to trace the three-quarters, it shows that 10:45, 9:45, and 8:45 are the three-quarters. So Hamid statement that he has to be at the field at 9:45 A.M is not correct.
