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atroni [7]
3 years ago
9

I need help asap no rocky

Mathematics
1 answer:
aev [14]3 years ago
3 0
The answer is the fourth option: rises 4 and then falls 14
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Pls help me with this
DedPeter [7]

Answer:

the volume of the cone would be approximately 490.09 m^3.

Step-by-step explanation:

The volume of a cone is pir^2h/3

So it would be pi*6^2*13/3

=pi*36*13/3

=pi*156

=490.09

Therefore, the volume of the cone would be approximately 490.09 m^3.

I hope this helped and have a good rest of your day!

7 0
2 years ago
Find the volume of each three dimensional figure (3 problems please help)
grin007 [14]

Answer:

Step-by-step explanation:

1) The solid is a cube. The formula for determining the volume of a cube is expressed as

Volume = s³

s = 5 cm

Therefore,

Volume = 5³ = 125 cm³

2) The solid is a cuboid. The formula for determining the volume of a cuboid is expressed as

Volume = lwh

l = 10 inches

w = 5 inches

h = 2 inches

Therefore,

Volume = 10 × 5 × 2 = 100 inches³

3) The solid is a square base pyramid. The formula for determining the volume of a square base pyramid is expressed as

Volume = Area of square base × height

Area of square base = 3² = 9 m²

h = 10 m

Volume = 9 × 10 = 90m³

8 0
3 years ago
There are more swimmers under 30 years old than there are age 50 and above.
garik1379 [7]

Answer:

true!

Step-by-step explanation:

this is more of a statement then a question.

7 0
2 years ago
Read 2 more answers
The mean one-way commute to work in Chowchilla is 7 minutes. The standard deviation is 2.4 minutes, and the population is normal
adell [148]

Answer:

The answer is below

Step-by-step explanation:

Given that:

The mean (μ) one-way commute to work in Chowchilla is 7 minutes. The standard deviation (σ) is 2.4 minutes.

The z score is used to determine by how many standard deviations the raw score is above or below the mean. It is given by:

z=\frac{x-\mu}{\sigma}

a) For x < 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

From normal distribution table,  P(x < 2) = P(z < -2.08) = 0.0188 = 1.88%

b) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table, P(2 < x < 11) = P(-2.08 < z < 1.67 ) = P(z < 1.67) - P(z < -2.08) = 0.9525 - 0.0188 = 0.9337  

c) For x = 11:

z=\frac{x-\mu}{\sigma}=\frac{11-7}{2.4} =1.67

From normal distribution table,  P(x < 11) = P(z < 1.67) = 0.9525

d) For x = 2:

z=\frac{x-\mu}{\sigma}=\frac{2-7}{2.4} =-2.08

For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table, P(2 < x < 5) = P(-2.08 < z < -0.83 ) = P(z < -0.83) - P(z < -2.08) =  0.2033- 0.0188 = 0.1845  

e) For x = 5:

z=\frac{x-\mu}{\sigma}=\frac{5-7}{2.4} =-0.83

From normal distribution table,  P(x < 5) = P(z < -0.83) = 0.2033

8 0
3 years ago
While grading her students' most recent quiz on equation solving, Mrs. Jones calculated that approximately forty percent of her
EastWind [94]

The given equation is,

3(-n+4)+5n=2n

Part 1:

Solve the above equation for n.

Using distributive property of multiplication,

\begin{gathered} -3n+3\times4+5n=2n \\ -3n+12+5n=2n \end{gathered}

Now, group the like terms.

-3n+5n-2n+12=0

Now, add the like terms.

\begin{gathered} -5n+5n+12=0 \\ 0=-12 \end{gathered}

0=-12 is a false statement.

Since we obtained a false statement, the given equation has no solution.

So, option b is correct.

Part 2:

The option (a) is n=3.

If while solving an equation, a single value is obtained for the variable, then the equation has only a single solution. If n=3 is obtained after solving the equation, then the student should chose option (a) as the answer.

The option (b) is "no solution".

While solving an equation, if we obtain an equation which is mathematically false, then the equation will have no solution. So, no solution is chosen when no value is obtained for n and the final equation is mathematically false.

The option (c) is "infinitely many solutions".

While solving an equation, if we obtain an equation which is mathematically correct such as 0=0, 7=7 etc., then the equation will have infinietly many solutions. So, infinitely many solutions is chosen when no value is obtained for n and the final equation is mathematically correct.

8 0
1 year ago
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