Answer:
1
Step-by-step explanation:
Substitute the value of the variable into the expression and simplify.
4-2-1=1
Answer: The widths of Kyle and Myla's boxes is the same as 2 ft.
Step-by-step explanation:
Formula : Volume of cuboidal box = length x width x height
Given: Kyle has a storage box that is 2 ft. Long, 3 ft. High, and has a volume of 12 ft³ .
Myla has a storage box that is 4 ft. High, 2 ft. Long, and has a volume of 16 ft³.
Hence, the widths of Kyle and Myla's boxes is the same as 2 ft.
By Hand
Step 1:
Put the numbers in order.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 2:
Find the median.
1, 2, 5, 6, 7, 9, 12, 15, 18, 19, 27.
Step 3:
Place parentheses around the numbers above and below the median.
Not necessary statistically, but it makes Q1 and Q3 easier to spot.
(1, 2, 5, 6, 7), 9, (12, 15, 18, 19, 27).
Step 4:
Find Q1 and Q3
Think of Q1 as a median in the lower half of the data and think of Q3 as a median for the upper half of data.
(1, 2, 5, 6, 7), 9, ( 12, 15, 18, 19, 27). Q1 = 5 and Q3 = 18.
Step 5:
Subtract Q1 from Q3 to find the interquartile range.
18 – 5 = 13.
12 inches go into one foot, so we can calculate the volume of the tank in inches to make the calculations that follow easier. Therefore, to calculate the volume of the tank, we use length x breadth x height = 4 x 2 x 2 = 16 square feet x 12 for square inches = 192 square inches.
Every 12 square inches Joseph can fit a one inch fish. The fish that he has are 3 inches long, therefore he can only fit one fish every 36 square inches.
That means that if we take the total volume of the tank and divide it by the space that a 3 inch fish will take up, we are left with 192/36 = 5.3 fish.
You cannot have a third of a fish, so we round off to the nearest whole number, and we determine that Joseph can put 5 fish in his new aquarium.
