Question

If a rectangle is 2 meters more than its width, and the area of it is 80 square meters, what is the length and width?

Answer 1

Ok I think it means that the length $l$ of the rectangle is 2 m more than is width $w$...
The area is A=$l*w=(w+2)*w=80$
so: $w^{2} +2w-80=0$
Solving this equation (using the quadratic formula) you get 2 solutons. The only acceptable is the positive one, i.e. $w=8 m$, the length will then be $l=w+2=8+2=10m$.