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Ede4ka [16]
3 years ago
8

2(x-3)^2+10=82 solve by isolating x

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0
We have the following equation:
 2 (x-3) ^ 2 + 10 = 82
 We must clear x.
 We pass the constant terms to one side of the equation:
 2 (x-3) ^ 2 = 82 - 10
 2 (x-3) ^ 2 = 72
 (x-3) ^ 2 = 72/2
 (x-3) ^ 2 = 36
 Square root to both members:
 x-3 = +/- root (36)
 x-3 = +/- 6
 The solutions are:
 x1 = 6 + 3 = 9
 x2 = -6 + 3 = -3
 Answer:
 
x1 = 9
 
x2 = -3
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we know that

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we have

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we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

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cos^{2}(x)=1-\frac{1}{4}

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Find tan(x)

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Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

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3 years ago
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