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Sliva [168]
3 years ago
12

Can someone help with this idk how to do it and pls explain.

Mathematics
2 answers:
V125BC [204]3 years ago
6 0
{35km + x = 140km} {140km - 35km= 105km} so the car traveled 105 kilometers.
gregori [183]3 years ago
3 0

Answer:

The car traveled 105 kilometers

Step-by-step explanation:

If the car started at 35 km, and it went to 140 km, then all you need to do is 135-30. That gives you 105

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Find the smallest 4 digit number such that when divided by 35, 42 or 63 remainder is always 5
alex41 [277]

The smallest such number is 1055.

We want to find x such that

\begin{cases}x\equiv5\pmod{35}\\x\equiv5\pmod{42}\\x\equiv5\pmod{63}\end{cases}

The moduli are not coprime, so we expand the system as follows in preparation for using the Chinese remainder theorem.

x\equiv5\pmod{35}\implies\begin{cases}x\equiv5\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{42}\implies\begin{cases}x\equiv5\equiv1\pmod2\\x\equiv5\equiv2\pmod3\\x\equiv5\pmod7\end{cases}

x\equiv5\pmod{63}\implies\begin{cases}x\equiv5\equiv2\pmod 3\\x\equiv5\pmod7\end{cases}

Taking everything together, we end up with the system

\begin{cases}x\equiv1\pmod2\\x\equiv2\pmod3\\x\equiv0\pmod5\\x\equiv5\pmod7\end{cases}

Now the moduli are coprime and we can apply the CRT.

We start with

x=3\cdot5\cdot7+2\cdot5\cdot7+2\cdot3\cdot7+2\cdot3\cdot5

Then taken modulo 2, 3, 5, and 7, all but the first, second, third, or last (respectively) terms will vanish.

Taken modulo 2, we end up with

x\equiv3\cdot5\cdot7\equiv105\equiv1\pmod2

which means the first term is fine and doesn't require adjustment.

Taken modulo 3, we have

x\equiv2\cdot5\cdot7\equiv70\equiv1\pmod3

We want a remainder of 2, so we just need to multiply the second term by 2.

Taken modulo 5, we have

x\equiv2\cdot3\cdot7\equiv42\equiv2\pmod5

We want a remainder of 0, so we can just multiply this term by 0.

Taken modulo 7, we have

x\equiv2\cdot3\cdot5\equiv30\equiv2\pmod7

We want a remainder of 5, so we multiply by the inverse of 2 modulo 7, then by 5. Since 2\cdot4\equiv8\equiv1\pmod7, the inverse of 2 is 4.

So, we have to adjust x to

x=3\cdot5\cdot7+2^2\cdot5\cdot7+0+2^3\cdot3\cdot5^2=845

and from the CRT we find

x\equiv845\pmod2\cdot3\cdot5\cdot7\implies x\equiv5\pmod{210}

so that the general solution x=210n+5 for all integers n.

We want a 4 digit solution, so we want

210n+5\ge1000\implies210n\ge995\implies n\ge\dfrac{995}{210}\approx4.7\implies n=5

which gives x=210\cdot5+5=1055.

5 0
3 years ago
Calculate the discriminant.<br><br> x2 – x – 2 = 0
nikitadnepr [17]
\Delta=(-1)^2-4\cdot1\cdot(-2)=1+8=9
6 0
3 years ago
Daniel opens a savings account and deposits $100 into it. Each year, the amount of money in his account increases by 5%. Use the
shtirl [24]

it will take him 33 years to reach $500

5 0
3 years ago
Read 2 more answers
URGENT! WILL MARK BRAINLIEST!
Sergeu [11.5K]

Answer:

Hi! Your answer will be : 599.37!

Step-by-step explanation:

8 0
3 years ago
3x+2&gt;2 and 3x less than or equal to 6
Y_Kistochka [10]
3x + 2 > 2
3x > 2 - 2
3x > 0
x > 0

3x < = 6
x < = 6

0 < x < = 6
4 0
3 years ago
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