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3 years ago

The magnitude of the weight of a 3.0 kg object on the surface of the earth is 29 N. True False

1 answer:

8 0

True

In fact, the weight of an object on the surface of the Earth is given by:
$F=mg$
where m is the mass of the object and $g=9.81 m/s^2$ is the gravitational acceleration on Earth's surface. If we use the mass of the object, m=3.0 kg, we find
$F=mg=(3.0 kg)(9.81 m/s^2)=29 N$

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Learn more about centripetal acceleration:

brainly.com/question/2562955

brainly.com/question/6372960

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