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4 years ago

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You ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. the reading on the

scale is you ride on an elevator that is moving with constant upward acceleration while standing on a bathroom scale. the reading on the scale is

1 answer:

Blababa [14]4 years ago

4 0

The reading on the scale is greater than your actual weight.

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Planet X has no atmosphere. This planet will most likely _____.

eduard

A) be too hot to support life

5 0

3 years ago

Read 3 more answers

A biker pedals hard to ride his bike to the top of a 44 m hill. He decides to let his bike coast down the hill, and is having so

Dafna11 [192]

Answer:

The bikers speed at the top of other hill is <u>25.82 m/s.</u>

Explanation:

Considering the biker is riding on a frictionless surface.

∴ There is no non-conservative or external force acting on the biker.

Hence we can conserve the energy of biker and bike as a system.

Let,

$h_{1}$ = 44m

$h_{2}$ = 10m

Since the biker starts from rest , his initial speed $v_{1}$ = 0 m/s

Let final speed of the bike at the top of other hill be $v_{2}$ .

∴ Initial Energy (at the top of 44m hill) = $mgh_{1}$

Final Energy (at the top of 10m hill) = $mgh_{2} + \frac{1}{2}mv_{2} ^{2}$ .

Conserving both the energies , we get

$mgh_{1}$ = $mgh_{2} + \frac{1}{2}mv_{2} ^{2}$

∴ $v_{2} = \sqrt{2g(h_{1}-h_{2} )}$

Substituting the values for g , $h_{1}$ , $h_{2}$ , we get

$v_{2}$ = 25.82 m/s

6 0

3 years ago

A)A certain medical machine emits x-rays with a minimum wavelength of 0.024 nm. One day, the machine has an electrical problem a

oee [108]

Answer:

(a) 0.032 nm

(b) 39,235 eV

(c) 70,267.8 eV

Explanation:

(a) The energy of a photon can be calculated using:

E = hc/λ equation (1)

where:

h = 4.13*10^-15 eV.s

c = 3*10^8 m/s

λ = 0.024*10^-9 m

Thus:

E = (4.13*10^-15)*(3*10^8)/0.024*10^-9 = 51,625 eV

Then we calculate 76% of this estimated energy and determine the new wavelength:

$E_{new} = 0.76*51625 = 39,235 eV$

Using equation (1) to determine the new wavelength:

λ $_{new} = \frac{h*c}{E_{new} }$

λ $_{new}$ = (4.13*10^-15)*(3*10^8)/39235 = 3.15*10^-11 m = 0.032 nm

(b) As calculated in part (a), the maximum x-ray energy this machine can produce is $E_{new} = 0.76*51625 = 39,235 eV$

(c) The energy of a Ka x-ray photon can be estimated using:

$E_{ka} = (10.2 eV)*(Z-1)^{2}$

where Z is the atomic number = 84.

$E_{ka} = (10.2 eV)*(84-1)^{2}$ = 70,267.8 eV

4 0

3 years ago

There are roughly 3 × 10−6 g of uranium per liter of seawater. Assuming there are 3.535 × 1020 gallons of seawater on earth, cal

Anvisha [2.4K]

Answer:

4 x 10^12 kg Uranium

Explanation:

As we know that 1 gallon = 3.785 L

Amount of Uranium in 1 L sea water = 3 x 10^-6 g

3.535 x 10^20 gallons = 3.535 x 10^20 x 3.785 L = 13.38 x 10^20 L

1 L of sea water contains = 3 x 10^-6 g Uranium

13.38 x 10^20 L of sea water contains = 13.38 x 10^20 x 3 x 10^-6 g Uranium

= 4 x 10^15 g = 4 x 10^12 kg Uranium

3 0

4 years ago

A parallel-plate capacitor in air has circular plates of radius 3.0 cm separated by 1.1 mm. Charge is flowing onto the upper pla

Yuki888 [10]

Answer:

2 x 10^14 N/Cs

Explanation:

radius, r = 3 cm

Area , A = 3.14 x 3 x 3 = 28.26 cm^2 = 28.26 x 10^-4 m^2

d = 1.1 mm = 1.1 x 10^-3 m

i = 5 A

Let time be t and electric field strength is E.

Charge, q = i x t = 5 t

q = C V

q = C x E x d

$5 t = \frac{\varepsilon _{0}A}{d}\times E\times d$

$E/t = \frac{5}{\varepsilon _{0}A}$

$E/t = \frac{5}{8.854\times 10^{-12}\times 28.26\times 10^{-4}}$

E/t = 2 x 10^14 N/Cs

5 0

3 years ago