The force exerted on the box is 56 N
Explanation:
The work done by a force on an object is given by
where
F is the magnitude of the force
d is the displacement of the object
is the angle between the direction of the force and of the displacement
For the box in this problem, we have:
W = 2240 J is the work done
d = 40 m is the displacement of the box
Assuming that the force is parallel to the displacement,
Solving the equation for F, we find the force exerted on the box:
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The correct answer to your question is 3.62
Answer:
W = 8.92 10² kJ
Explanation:
For this exercise they give us the strength, we must calculate the distance traveled, for this we need the rocket acceleration let's use Newton's second law
F = m a
a = F / m
a = 20 103/1400
a = 14.29 m/s²
With kinematics we can find the distance traveled
² = v₀² + 2 a x
x = ( ²-v₀²) / 2 a
x = (50² -35²) / 2 14.29
x = 1275 / 28.58
x = 44.61 m
Let's calculate the work
W = F.d
The bold is vector; as indicated by the force is in the direction of movement the scalar product is reduced to the ordinary product
W = F d
W = 20 10³ 44.61
W = 8.92 10⁵ J
W = 8.92 10² kJ
Answer: 15.6 metres
Explanation:
Given that:
length of wave (λ)= ?
Frequency of wave F = 28 Hertz
Speed of wave (V) = 437 m/s
The wavelength is the distance covered by the wave in one complete cycle. It is measured in metres, and represented by the symbol λ.
So, apply V = F λ
Make λ the subject formula
λ = V / F
λ = 437 m/s / 28 Hertz
λ = 15.6 m
Thus, the length of the wave is 15.6 metres