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Alex777 [14]
3 years ago
14

Green sea turtles eat sea grass that grows on the sea floor. Seagrass, a foundation species, provides an important breeding grou

nd for fish and other marine organisms. A conservation program for the green sea turtles plans to introduce more turtles into an ecosystem. What could be the immediate effect of this on the ecosystem?
A) More species of fish would migrate to the region.
B) The new turtles would drive out the existing population.
C) The region would witness a spurt in the growth of sea grass.
Eliminate
D) There would be a decrease in the population of marine organisms.
Physics
2 answers:
d1i1m1o1n [39]3 years ago
3 0
The answer is D. <span> There would be a decrease in the population of marine organisms. </span>
Agata [3.3K]3 years ago
3 0

The answer is D.  There would be a decrease in the population of marine organisms.


Populations are effected not only because of predation but also due to habitat loss caused by the introduction of a new species into the ecosystem. If more sea turtles are added into the region they would deplete the sea grass, causing a decrease in the population of marine organisms due to the loss of breeding grounds and food source.

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Which parts of Dalton’s atomic theory had to be revised
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3 years ago
A "biconvex" lens is one in which both surfaces of the lens bulge outwards. Suppose you had a biconvex lens with radii of curvat
Stolb23 [73]

Answer: f=150cm in water and f=60cm in air.

Explanation: Focal length is a measurement of how strong light is converged or diverged by a system. To find the variable, it can be used the formula:

\frac{1}{f} = (nglass - ni)(\frac{1}{R1} - \frac{1}{R2}).

nglass is the index of refraction of the glass;

ni is the index of refraction of the medium you want, water in this case;

R1 is the curvature through which light enters the lens;

R2 is the curvature of the surface which it exits the lens;

Substituting and calculating for water (nwater = 1.3):

\frac{1}{f} = (1.5 - 1.3)(\frac{1}{10} - \frac{1}{15})

\frac{1}{f} = 0.2(\frac{1}{30})

f = \frac{30}{0.2} = 150

For air (nair = 1):

\frac{1}{f} = (1.5 - 1)(\frac{1}{10} - \frac{1}{15})

f = \frac{30}{0.5} = 60

In water, the focal length of the lens is f = 150cm.

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5 0
4 years ago
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Could someone please help me with this problem? I’m thinking that they both will have the same force because they have the same
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You would be correct
7 0
4 years ago
A uniform, spherical, 1900.0 kg shell has a radius of 5.00 m. Find the gravitational force this shell exerts on a 1.80 kg point
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Answer:

F=9.09\times 10^{-9} N

Explanation:

We are given that

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Distance between two masses=r=5.01 m

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Gravitational force

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Using the formula

F=6.67\times 10^{-11}\times \frac{1900\times 1.80}{(5.01)^2}

F=9.09\times 10^{-9} N

Hence,the gravitational force =F=9.09\times 10^{-9} N

6 0
3 years ago
Which transformation could take place at the anode of an electrochemical cell?
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As I found out the choices for your question which are: 

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