I will assume that by "Evaluate 8(7x--3) when x=9" you meant:
"Evaluate 8(7x-3) when x=9."
First, substitute 9 for x in 7x-3: 7(9)-3 = 60. Rewrite the problem as:
8(60). Multiply. Answer: 480
Answer:
50.272 in^2
Step-by-step explanation:
Step one:
Given data
Circles are described using the diameter parameter
Diameter of the circle is 8 inches
radius = 4 inche= d/2
Step two:
The area of the circle is
A= πr^2
A= 3.142*4^2
A=3.142*16
A=50.272 in^2
Answer:
I think so, but don't lose sight
Answer:
I think your answer would be C I am not sure the way I worked it out says C. I hope this helps you out.
Answer:
![(-\infty,\frac{25}{24}]](https://tex.z-dn.net/?f=%28-%5Cinfty%2C%5Cfrac%7B25%7D%7B24%7D%5D)
Step-by-step explanation:
Assuming 
is a variable:
![4i-4(i+2)\geq6(8i-8)\\\\4i-4i+2\geq48i-48\\\\2\geq48i-48\\\\50\geq48i\\\\\frac{50}{48}\geq i\\ \\\frac{25}{24}\geq i\\ \\i\leq\frac{25}{24}\\ \\(-\infty,\frac{25}{24}]](https://tex.z-dn.net/?f=4i-4%28i%2B2%29%5Cgeq6%288i-8%29%5C%5C%5C%5C4i-4i%2B2%5Cgeq48i-48%5C%5C%5C%5C2%5Cgeq48i-48%5C%5C%5C%5C50%5Cgeq48i%5C%5C%5C%5C%5Cfrac%7B50%7D%7B48%7D%5Cgeq%20i%5C%5C%20%5C%5C%5Cfrac%7B25%7D%7B24%7D%5Cgeq%20i%5C%5C%20%5C%5Ci%5Cleq%5Cfrac%7B25%7D%7B24%7D%5C%5C%20%5C%5C%28-%5Cinfty%2C%5Cfrac%7B25%7D%7B24%7D%5D)
