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Tresset [83]
3 years ago
14

Solve x2-x-5/2 = 0 using the quadratic formula. the answer choices are in the picture

Mathematics
1 answer:
allsm [11]3 years ago
7 0

Answer:

Exact Form:  x =( 1 ± √ 11) /2

It's the first one.

Step-by-step explanation:

Solve the equation for  x  by finding  a ,  b , and  c  of the quadratic then applying the quadratic formula.

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It is known that a cable with a​ cross-sectional area of 0.300.30 sq in. has a capacity to hold 2500 lb. If the capacity of the
vesna_86 [32]

Answer:

0.84 square in

Step-by-step explanation:

Since the capacity of the cable is proportional to its​ cross-sectional area. If a cable that is 0.3 sq in can hold 2500 lb then per square inch it can hold

2500 / 0.3 = 8333.33 lb/in

To old 7000 lb it the cross-sectional area would need to be

7000 / 8333.33 = 0.84 square in

5 0
2 years ago
Read 2 more answers
Can someone please help me
Aleks04 [339]

Answer:75

Step-by-step explanation: Find the area of the triangle which is 1/2 base times height. The base is 9 while the height is 4+5+1 which is 10. 10 times 9 is 90 and half of 90 is 45. Then find the area of the rectangle which is length times width which is 5 times 3 which is 15. Then subtract 15 from 90 which gets you the answer 75.

7 0
3 years ago
Read 2 more answers
MATH HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
sergey [27]

Answer:

The answer is 2/5

Step-by-step explanation:

10/15 simplified is 2/5

5 0
2 years ago
Read 2 more answers
Which estimate best describes the area under the curve in square units?
stepladder [879]
<span>I think any of those estimates are correct since we don't have a value for the width and length so acquiring the actual measurement its impossible. All possible answers are correctly written in square units.</span>
3 0
3 years ago
Rationalize the expression. Write it in simplest form.<br><br> 9x/√-2x-11
GenaCL600 [577]
This appears to be just an expression we are simplifying, not an equation we are solving.  I THINK you are saying that the expression looks like this:
\frac{9x}{ \sqrt{-2x-11} }
If you rationalize the denominator, you would get this expression:
\frac{9x}{ \sqrt{-2x-11} } * \frac{ \sqrt{-2x-11} }{ \sqrt{-2x-11} }
which, after simplifying, looks like this:
\frac{9x \sqrt{-2x-11} }{-2x-11}
and that's as simple as I can see that one getting.  You can't factor anything out of the denominator to cancel with the numerator, so I think you're as simple as you can get there!
3 0
3 years ago
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