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Nadusha1986 [10]
3 years ago
6

How do you write the difference of a number and eight, divided by ten

Mathematics
2 answers:
ch4aika [34]3 years ago
7 0

Answer:

(x-8)/10

Step-by-step explanation:

-------

Butoxors [25]3 years ago
5 0

(X - 8)/10 or (8 -X)/10

The unknown number can be given as X

The difference between the number and 8 can be given as 8 -X or X - 8

The dividing it by 10 will give (x-8)/10 or (8-x)/10 depending on the value of the unknown number X

You might be interested in
N is a positive integer.Explain why n(n-1) must be an even number.
V125BC [204]

Answer:

n and (n - 1) are consecutive integers.

Step-by-step explanation:

We are given 'n', a positive integer.

This 'n' can either be odd or even.

Case I:

When 'n' is odd

The n - 1 is even.

Note that the product of odd and even is always even. That is the product of n and (n - 1) is even.

Case II:

when 'n' is even

Then n - 1 is odd.

Again, using the similar logic we can say that the product of n and n - 1 should be even because here, 'n - 1' is even and 'n' is odd.

4 0
3 years ago
Amanda's gross annual salary is $62,112 what is the maximum amount of rent she can afford to pay
abruzzese [7]
Answer is 1866 dollars
7 0
3 years ago
i have only a few more questions! I took screen shots of them, so flip threw the picture. all of them are different questions!
givi [52]

Answer:

3) C.

4) B.

5) C.

Step-by-step explanation:


4 0
3 years ago
Find a and b so that f(x) = x^3 + ax^2 + b will have a critical point at (2,3).
Digiron [165]

Using the critical point concept, it is found that a = -3 and b = 7.

<h3>What are the critical points of a function?</h3>
  • The critical points of a function are the values of x for which:

f^{\prime}(x) = 0

In this problem, the function is:

f(x) = x^3 + ax^2 + b

Hence, the derivative is:

f^{\prime}(x) = 3x^2 + 2ax

Then:

f^{\prime}(x) = 0

3x^2 + 2ax = 0

x(3x + 2a) = 0

x = 0

3x + 2a = 0

3x = -2a

x = -\frac{2a}{3}

Since the critical point is at x = 2, we have that:

-\frac{2a}{3} = 2

-2a = 6

2a = -6

a = -3

Then:

f(x) = x^3 - 3x^2 + b

Critical point at (2,3) means that when x = 2, y = 3, then:

3 = 2^3 - 3(2)^2 + b

8 - 12 + b = 3

b = 7

You can learn more about the critical point concept at brainly.com/question/2256078

4 0
1 year ago
(09.04 mc) a circle has its center at (−1, 2) and a radius of 3 units. what is the equation of the circle? (x − 1)2 + (y + 2)2 =
Reil [10]
General formula to make an equation of circle
(x - a)² + (y - b)² = r²


Given:
the center (a,b) = (-1,2)
the radius r = 3

Solution:
plug the numbers to the formula
(x - a)² + (y - b)² = r²
(x - (-1))² + (y - 2)² = 3²
(x + 1)² + (y - 2)² = 9
The answer is the last option
4 0
2 years ago
Read 2 more answers
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