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Gwar [14]
4 years ago
10

Research how the body uses feedback mechanism to decrease the heart rate after exercise. what specifically happens in the body t

o bring the heart rate back down?
Biology
1 answer:
maw [93]4 years ago
6 0
<span>A negative feedback loop works by adjusting an output, such as heart rate, in response to a change in input, such as blood pressure. A basic loop consists of a receptor, a control center and an effector. If you are at rest and your blood pressure increases, pressure receptors in your carotid arteries detect this change in input and send nerve impulses to the medulla of your brain, or control center. This signals the brain to reduce nerve impulses that stimulate your heart muscle, an effector, to contract. Your heart contracts more slowly and your output, or heart rate decreases, causing your blood pressure to decrease to within target levels.</span>
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8 0
3 years ago
scalloped (sd) is an X-linked recessive and ebony (e) is an autosomal recessive mutation. What proportion of scalloped, ebony fe
alisha [4.7K]

Answer:

1/16

Explanation:

  • scalloped (Xsd) is an X-linked recessive trait to Xsd+ (wild type)
  • ebony (e) is an autosomal mutation recessive to e+ (wild type).

The two genes are independent because they are located on different chromosomes.

<h3><u>Parental generation:</u></h3>

True breeding scalloped female wild type for ebony (<em>Xsd Xsd e+e+</em>) mates with a true breeding male mutant only for ebony (<em>Xsd+ Y ee</em>).

The female only produces <em>Xsd e+</em> gametes. The male produces <em>Xsd+ e</em> or <em>Y e</em> gametes.<u> Therefore, the F1 females will have the genotype </u><u><em>Xsd Xsd+ e e+ </em></u><u>and the F1 males will have the genotype </u><u><em>Xsd Y e e+.</em></u>

If you complete a Punnett Square with the gametes the two F1 individuals can produce, you will get all the F2 proportions. The scalloped, ebony females have a<em> Xsd Xsd e e</em> genotype and appear in a 1/16 proportion.

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Answer:

commercial agriculture

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