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Elina [12.6K]
2 years ago
6

In ΔCDE, the measure of ∠E=90°, the measure of ∠D=50°, and DE = 8. 1 feet. Find the length of CD to the nearest tenth of a foot

Mathematics
1 answer:
Luden [163]2 years ago
3 0

Answer:

  12.6 ft

Step-by-step explanation:

Trig functions relate the sides and angles in a right triangle. Here, we're given an angle and an adjacent side, and we're asked to find the hypotenuse. The relevant trig relation is ...

  Cos = Adjacent/Hypotenuse

  cos(50°) = DE/CD = (8.1 ft)/CD

Solving for CD, we find ...

  CD = (8.1 ft)/cos(50°) ≈ 12.601 ft

The length of CD is about 12.6 feet.

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Engineers must consider the breadths of male heads when designing helmets. The company researchers have determined that the popu
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Answer:

a) 3.3352 inches.

b) 8.2648 inches.

Step-by-step explanation:

When the distribution is normal, we use the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this question:

\mu = 5.8, \sigma = 1.2

A. What is the minimum head breadth that will fit the clientele?

This is the 2nd percentile, which is X when Z has a pvalue of 0.02. So X when Z = -2.054.

Z = \frac{X - \mu}{\sigma}

-2.054 = \frac{X - 5.8}{1.2}

X - 5.8 = -2.054*1.2

X = 3.3352

So the minimum head breadth that will fit the clientele is 3.3352 inches.

B. What is the maximum head breadth that will fit the clientele?

The 100-2 = 98th percentile, which is X when Z has a pvalue of 0.98. So X when Z = 2.054.

Z = \frac{X - \mu}{\sigma}

2.054 = \frac{X - 5.8}{1.2}

X - 5.8 = 2.054*1.2

X = 8.2648

So the maximum head breadth that will fit the clientele is 8.2648 inches.

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