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rosijanka [135]
3 years ago
14

The answer choices are in the attachments

Mathematics
1 answer:
tatiyna3 years ago
8 0
The first dropdown box answer is "reflection over the y axis"

See the attached image.

Note how corresponding points simply have the x coordinate negated. For example, A and M correspond
A = (2,8)
M = (-2,8)
The only difference between these two points is the x coordinate is positive for A, and negative for M

The same applies for B and N, C and O, etc etc

Whenever you negate x coordinates only, a reflection over the y axis occurs. This is the rule (x,y) ---> (-x,y)

-----------------------------------------------------------------------------------

The second dropdown box answer is the second choice

We can see this by adding 3 to the x coordinate of point M to go from -2 to 1 (-2+3 = 1). So the answer must have point V with an x coordinate of 1. The only answer choice that fits is choice 2. 


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Move triangle ABC so it lies on top of triangle DEF, triangle GHI, and triangle JKL. How many units do you have to move triangle
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Answer:

See explanation

Step-by-step explanation:

The question is incomplete, as the diagram of coordinates of the three triangles are not given.

A general explanation is as follows:

First, record the coordinates of the corresponding points of the three triangles.

For instance; In triangles ABC, DEF and GHI; A, D and G are corresponding points.

Now, assume the coordinates are:

A = (1,1)

D = (1,5)

G= (-2,1)

Point D is 4 points to the right of A;

i.e.

D =(1,1+4) = (1,5)

Hence, ABC will be moved 4 units right to lie on DEF

Similarly, point G is 3 units down of A

i.e.

G =(1-3,1) = (-2,1)

Hence, ABC will be moved 3 units down to lie on GHI.

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3 years ago
Eight times the sum of a number and six is 80
Pachacha [2.7K]

8*(n+6)=80

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6 0
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The language arts teacher wants to know whether the students in the entire school prefer a debate or an speech. The teacher draw
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Find the distance between the two points (-5, -2) and T(-3, 4).
Ulleksa [173]

Answer:

\displaystyle d = 2\sqrt{10}

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS<u> </u>

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)

<u>Algebra II</u>

  • Distance Formula: \displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Step-by-step explanation:

<u>Step 1: Define</u>

Point (-5, -2) → x₁ = -5, y₁ = -2

Point (-3, 4) → x₂ = -3, y₂ = 4

<u>Step 2: Find distance </u><em><u>d</u></em>

Simply plug in the 2 coordinates into the distance formula to find distance <em>d</em>

  1. Substitute in points [Distance Formula]:                                                       \displaystyle d = \sqrt{(-3+5)^2+(4+2)^2}
  2. [√Radical] (Parenthesis) Add:                                                                        \displaystyle d = \sqrt{(2)^2+(6)^2}
  3. [√Radical] Evaluate exponents:                                                                    \displaystyle d = \sqrt{4+36}
  4. [√Radical] Add:                                                                                               \displaystyle d = \sqrt{40}
  5. [√Radical] Simplify:                                                                                         \displaystyle d = 2\sqrt{10}
4 0
3 years ago
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