Ask question

Ask question

All categories

3 years ago

6

Kara bought a DVD for $22 and a cd for less then the cost of the DVD. Let c represent the cost of the cd. Write an inequality to

show the cost of the cd

1 answer:

shepuryov [24]3 years ago

3 0

C<d

The cd costs less than the dvd, therefore, the cd is less than (or <) then the dvd

You might be interested in

Solve the inequality 2x>30+5/4x

insens350 [35]

Answer:

Step-by-step explanation:

$2x > 30+\frac{5}{4x} \\2x-\frac{5}{4x} > 30\\\frac{8x^2-5}{4x} > 30\\case~1\\if~x > 0\\8x^2-5 > 120x\\8x^2-120x > 5\\x^2-15x > \frac{5}{8} \\adding~(-\frac{15}{2} )^2~to~both~sides\\(x-\frac{15}{2} )^2 > \frac{5}{8}+\frac{225}{4} \\(x-\frac{15}{2} )^2 > \frac{455}{8} \\x-\frac{15}{2} < -\sqrt{\frac{455}{8} } \\x < \frac{15}{2}-\sqrt{\frac{455}{8} } \\or~x < 0\\rejected~as~x > 0$

$x-\frac{15}{2} > \sqrt{\frac{455}{8} } \\x > \frac{15}{2} +\sqrt{\frac{455}{8} }$

case~2

$if~x < 0\\8x^2-5 < 120x\\8x^2-120x < 5\\x^2-15x < \frac{5}{8} \\adding~(-\frac{15}{2} )^2\\(x-\frac{15}{2} )^2 < \frac{5}{8} +(-\frac{15}{2} )^2\\|x-\frac{15}{2} | < \frac{5+450}{8} \\-\sqrt{\frac{455}{8} } < x-\frac{15}{2} < \sqrt{\frac{455}{8} } \\\frac{15}{2} -\sqrt{\frac{455}{8} } < x < \frac{15}{2} +\sqrt{\frac{455}{8} } \\but~x < 0\\7.5-\sqrt{\frac{455}{8} } < x < 0$

8 0

1 year ago

PLEASE HELLLLLLLLLLP

DedPeter [7]

Answer:It would be cut in half

Step-by-step explanation:The momentum of the ball is what speeds it up, like the engine to the car. It needs it to run, so if you cut it in half the speeds are cut in half.

5 0

3 years ago

Evaluate 64 divided by [4 x (27 - 10)]

KatRina [158]

Using PEMDAS,
27-10=17
17*4=68
64/68=0.94 (rounded to the nearest hundredth)

8 0

3 years ago

Read 2 more answers

Help me and fast! And please show work!

tekilochka [14]

Answer:

171

Step-by-step explanation:

fbgetjmnryjnmyjnmryjnhm

6 0

2 years ago

Read 2 more answers

How do you find the sine, cosine, and tangent values on the unit circle not in the first quadrant? Provide an example, and how y

gizmo_the_mogwai [7]

A point (-0.8, 0.6) will be a point on the unit circle in the second quadrant. Since it is a unit circle, its radius is 1, and we have
sin(α) = y = 0.6
cos(α) = x = -0.8
tan(α) = y/x = 0.6/-0.8 = -0.75

The angle is α = arccos(-0.8) ≈ 143.13°

______
For the unit circle, the trig values are always the coordinates or their ratio as shown above, regardless of quadrant.

7 0

2 years ago