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REY [17]
3 years ago
6

Kara bought a DVD for $22 and a cd for less then the cost of the DVD. Let c represent the cost of the cd. Write an inequality to

show the cost of the cd
Mathematics
1 answer:
shepuryov [24]3 years ago
3 0
C<d  

The cd costs less than the dvd, therefore, the cd is less than (or <) then the dvd
You might be interested in
Use the fractions 36in./1yd and 2.54 cm/1 in convert 3yd to cm
Flura [38]
Ndiuewuneqdkiqjdqjiodqeiojqdoiqdioaejdijeioeajdihoqedjioqedjoiqhioeqoieqjd
6 0
2 years ago
What are three equivalent ratios 14/2
Taya2010 [7]

Answer:

  • 7/1
  • 21/3
  • 532/76

Step-by-step explanation:

Reduce the ratio to lowest terms, then multiply numerator and denominator by any same value to get another equivalent.

  \dfrac{14}{2}=\dfrac{2\cdot 7}{2\cdot 1}=\dfrac{7}{1}\\\\=\dfrac{3\cdot 7}{3\cdot 1}=\dfrac{21}{3}\\\\=\dfrac{76\cdot 7}{76\cdot 1}=\dfrac{532}{76}

3 0
3 years ago
Please Help!<br><br> Car X travels 174 miles in 3 hours.
DiKsa [7]

Answer:

The graph =

<h3>y = 58x</h3>

Step-by-step explanation:

(a)

distance covered (y) = 174 miles

time taken (x) = 3 hours

Therefore the points = (3, 174) and (0, 0) = stationary position

Find the gradient (m)

m = 174-0 / 3-0

m = 58

Therefore the equation =

<h3>y = 58x</h3>

(distance = 58 × time)

For the distance = 174 and time = 3 hours, the equation to find either distance or time = y = 58x

(b) the graph is constant, because the time and distance are also contant when the speed used is the same.

____________________

#IndonesianPride - kexcvi

5 0
2 years ago
7. In some places, a suspension bridge is the only passage over a river. The height of one such bridge, h, in metres, above the
Cloud [144]
Sure. The function is a parabola. Because the coefficient of the x^2 term is positive, it opens upward. that means that it vertex is a minimum point.

You can verify that the vertex is (0,24). That means that at the point x=0, the height of the bridge is 24m. So if the level water rises below 24 m, the bridge is safe to use.
4 0
3 years ago
Morgan made a mistake when subtracting the rational expressions below 3t^2-4t+1/t+3-t^2+2t+2/t+3=2t^2-2t+3/t+3. What was Morgan'
marusya05 [52]
<h3>Answer: Choice D. </h3>

Morgan forgot to distribute the negative sign to two of the terms in the second expression.

=============================================================

Explanation:

Focus on the numerators.

We have (3t^2-4t+1) as the first numerator and we subtract off (t^2+2t+2) as the second numerator.

Morgan needs to simplify (3t^2-4t+1)-(t^2+2t+2) for the numerator.

Mistakenly, she had these steps

(3t^2-4t+1)-(t^2+2t+2)

3t^2-4t+1-t^2+2t+2 .... her mistake made here

(3t^2-t^2)+(-4t+2t)+(1+2)

2t^2-2t+3

All of this applies to the numerator. The denominator stays at t+3 the entire time. So effectively we can ignore it on a temporary basis.

Here's what Morgan should have for her steps when simplifying the numerator.

(3t^2-4t+1)-(t^2+2t+2)

3t^2-4t+1-t^2-2t-2 ..... distribute the negative

(3t^2-t^2)+(-4t-2t)+(1-2)

2t^2-6t-1

Note in the second step, the negative outside flips the sign of each term in the second parenthesis.

Therefore,

\frac{3t^2-4t+1}{t+3}-\frac{t^2+2t+2}{t+3}\\\\\frac{(3t^2-4t+1)-(t^2+2t+2)}{t+3}\\\\\frac{3t^2-4t+1-t^2-2t-2}{t+3}\\\\\frac{2t^2-6t-1}{t+3}\\\\

which means \frac{3t^2-4t+1}{t+3}-\frac{t^2+2t+2}{t+3}=\frac{2t^2-6t-1}{t+3}, \ \ \text{ where } t \ne -3\\\\

Side notes:

  • The fractions can only be subtracted since the denominators are the same.
  • We have t \ne -3 to avoid a division by zero error.
  • Rational expressions are a fraction, or ratio, of two polynomials.
5 0
2 years ago
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