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Tom [10]
4 years ago
6

Point s is between r and t on segment rt . use the given information to write on equation in terms of x. solve the equation. the

n find rs and st. rs = 2x + 10 st = x - 4 rt = 21 rs = st =
Mathematics
2 answers:
Juli2301 [7.4K]4 years ago
7 0
RS + ST = RT
The equation is:
2 x + 10 + x - 4 = 21
3 x + 6 = 21
3 x = 21 - 6
3 x = 15
x = 15 : 3
x = 5
RS = 2 * 5 + 10 = 10 + 10 = 20
ST = 5 - 4 = 1
Answer: Segment RS = 20 and ST = 1
alisha [4.7K]4 years ago
4 0

Answer:

Step-by-step explanation:

the answer is 10

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Art and his friends spent $62 at the movies. Admission tickets cost $12 apiece, and a bucket of popcorn costs $7. Which equation
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Answer: 12t+7p=62

Step-by-step explanation:

8 0
3 years ago
The two stadiums with the largest capacities are Marshfield Stadium and Bowden Stadium. Marshfield Stadium has a capacity of 7,6
Rina8888 [55]

Answer: Capacity of Marshfield Stadium is 109,015 and capacity of Bowden is Bowden.

Step-by-step explanation:

Let x = Capacity of Marshfield Stadium.

y = Capacity of Bowden.

As per given, we have

x - y = 7,675               (i)

x+y  =  210,355               (ii)

2x = 218030    (iii)

\Rightarrow\ x= \dfrac{218030}{2}\\\\\Rightarrow\ x= 109015

Put value of x in (i) , we get

109015 - y = 7675

⇒ y= 109015 - 7675

⇒ y= 101,340

Hence, capacity of Marshfield Stadium is 109,015 and capacity of Bowden is Bowden.

6 0
3 years ago
I NEED HELP ASAP PLEASEEEE​
spin [16.1K]

Answer:

Step-by-step explanation:

1) Find the Mean of all the numbers.

3+4+5+7+10+12+15=56

56/7=8 mean is 8

Now We Calculate Standard Deviation:

S=\sqrt{(3-8)^2+(4-8)^2+(5-8)^2+(7-8)^2+(10-8)^2+(12-8)^2+(15-8)^2}

You take each number from the problem i.e 3,4,5...

and then you subtract the mean from it and then square it.

S=\sqrt{(-5)^2+(-4)^2+(-3)^2+(-1)^2+(2)^2+(4)^2+(7)^2}

S=\sqrt{25+16+9+1+4+16+49}

S=\sqrt{120}

S=\sqrt{120}/7

7 is the amount of data units given in the problem.

120/7=17.1428571429

\sqrt{17.1428571429} =4.1403933560541

Nearest hundredth=4.14

5 0
3 years ago
​claim: the mean pulse rate​ (in beats per​ minute) of adult males is equal to 6969 bpm. for a random sample of 125125 adult​ ma
RoseWind [281]

Answer:

t=0.21

Step-by-step explanation:

Given  \bar x=69.2, s=10.9, n=125and a population mean \mu=69.

#We state our hypothesis as:

H_o:\mu=69\\\\H_a:\mu\neq 69

The evidence available should validate either the null or alternative hypothesis.

#We calculate the test statistic as:

t=\frac{\bar x-\mu_}{s/\sqrt{n}}\\\\\\=\frac{69.2-69}{10.9/\sqrt{125}}\\\\\\=0.2051

\approx0.21

Hence, the test statistic is t=0.21

4 0
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