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3 years ago

What's the elapsed time between 2:16am and 8:10pm

Mathematics

2 answers:

svet-max [94.6K]3 years ago

6 0

2:16+5:54= 8:10 I think this is the answer
5 hours and 54 minutes

Amiraneli [1.4K]3 years ago

6 0

The answer is 5 hours and 54 minutes

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Relative density was determined for one sample of second-growth Douglas fir 2 x 3 4s with a low percentage of juvenile wood and

Citrus2011 [14]

Answer:

0.03865

Step-by-step explanation:

Since the true density for the two types of trees are given, we would evaluate the average for both of them

Low percentage of juvenile wood density = 0.523 and 0.0543

Average density = 0.523 + 0.0543/2

Average density = 0.55015

Moderate percentage of juvenile wood density = 0.489 and 0.0450

Average density = 0.489 + 0.0450/2

Average density = 0.5115

Therefore, difference in true average density for the two woods are = 0.55015 - 0.51150

= 0.03865

5 0

3 years ago

When studying radioactive material, a nuclear engineer found that over 365 days,

Gnom [1K]

Answer:

a) The mean number of radioactive atoms that decay per day is 81.485.

b) 0% probability that on a given day, 50 radioactive atoms decayed.

Step-by-step explanation:

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\lambda}*\lambda^{x}}{(x)!}$

In which

x is the number of sucesses

e = 2.71828 is the Euler number

$\lambda$ is the mean in the given interval.

a. Find the mean number of radioactive atoms that decayed in a day.

29,742 atoms decayed during 365 days, which means that:

$\lambda = \frac{29742}{365} = 81.485$

The mean number of radioactive atoms that decay per day is 81.485.

b. Find the probability that on a given day, 50 radioactive atoms decayed.

This is P(X = 50). So

$P(X = 50) = \frac{e^{-81.485}*(81.485)^{50}}{(50)!} = 0$

0% probability that on a given day, 50 radioactive atoms decayed.

5 0

2 years ago

Identify the like terms in the list.

MrRa [10]

Answer:

17x and 3x

Step-by-step explanation:

like terms are terms that have the same variables and powers. The coefficients do not need to match. Unlike terms are two or more terms that are not like terms, i.e. they do not have the same variables or powers. The order of the variables does not matter unless there is a power.

8 0

1 year ago

n a Gallop poll of 1012 randomly selected adults, 9% said that cloning of humans should be allowed. We are going to use a .05 si

Vanyuwa [196]

Answer:0.1446

Step-by-step explanation:

Let p be the population proportion of adults say that cloning of humans should be allowed.

As per given , the appropriate set of hypothesis would be :-

$H_0: p\geq0.10\\\\ H_a: p$

Since $H_a$ is left-tailed and sample size is large(n=1012) , so we perform left-tailed z-test.

Given : The test statistic for this test is -1.06.

P-value for left tailed test,

P(z<-1.06)=1-P(z<1.06) [∵P(Z<-z)=1-P(Z<z]

= $1-0.8554=0.1446$ (Using z-value table.)

Hence, the p-value for this test statistic= 0.1446

4 0

2 years ago

What is 6 1/4 - 3 1/3

Anettt [7]

Hey There!

Remember, first find the gcf of 4,3 in this problem it is 12.

Steps to solve

1.6 $\frac{1}{4}$ - 3 $\frac{1}{3}$

2.6 $\frac{1}{4}$ - 3 $\frac{1}{3}$ = 2 $\frac{11}{12}$

So, The answer is <span>2 $\frac{11}{12}$ </span>

Hope This Helps :)

6 0

3 years ago

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