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Nimfa-mama [501]
3 years ago
13

What is the slope of the line through (-2,3) and (1,1)?

Mathematics
1 answer:
son4ous [18]3 years ago
6 0
The slope of the line is -2/3.

This is found by using the equation y2 - y1/x2 - x1. Filling in for each factor, you would have 1-3/1+2 (since subtracting a negative makes it positive). This will give you a final answer of -2/3.

Here is a graph of the full equation of the line.

I hope this helps!

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3. Which linear equation corresponds to the line graph?
iogann1982 [59]

Answer:

Y=1/3x

Step-by-step explanation:

1) there is no y intercept as x=0 when y=0 so that rules out y=x-2

2) next, we will use the formula for slope to find the value of m

Y2-Y1/X2-X1

Where y2=-1

Y1=0

X2=-3

X1=0

So

-1-0/-3-0=-1/-3

Aka 1/3

So y=1/3x

Hope this helps!

3 0
3 years ago
Find the missing side length
DochEvi [55]
Tan=o/adj
Tan=60/b
B=60/tan(68)
I don't have a calculator on me but you should be able to do it from there
3 0
3 years ago
Find the area of each regular polygon. Round your answer to the nearest tenth if necessary.
tatuchka [14]

*I am assuming that the hexagons in all questions are regular and the triangle in (24) is equilateral*

(21)

Area of a Regular Hexagon: \frac{3\sqrt{3}}{2}(side)^{2} = \frac{3\sqrt{3}}{2}*(\frac{20\sqrt{3} }{3} )^{2} =200\sqrt{3} square units

(22)

Similar to (21)

Area = 216\sqrt{3} square units

(23)

For this case, we will have to consider the relation between the side and inradius of the hexagon. Since, a hexagon is basically a combination of six equilateral triangles, the inradius of the hexagon is basically the altitude of one of the six equilateral triangles. The relation between altitude of an equilateral triangle and its side is given by:

altitude=\frac{\sqrt{3}}{2}*side

side = \frac{36}{\sqrt{3}}

Hence, area of the hexagon will be: 648\sqrt{3} square units

(24)

Given is the inradius of an equilateral triangle.

Inradius = \frac{\sqrt{3}}{6}*side

Substituting the value of inradius and calculating the length of the side of the equilateral triangle:

Side = 16 units

Area of equilateral triangle = \frac{\sqrt{3}}{4}*(side)^{2} = \frac{\sqrt{3}}{4}*256 = 64\sqrt{3} square units

4 0
3 years ago
A conjecture and the two-column proof used to prove the conjecture are shown. Given: S is the midpoint of segment R T. Segment R
Scrat [10]

given: s is the midpoint of rt

definition of midpoint: rs st

given: st xy

transitive property of congruence: rs xy

6 0
3 years ago
Read 2 more answers
3(2x+5)=36<br>what is the value of x
Bond [772]
3(2x+5)=36\\&#10;6x+15=36\\&#10;6x=21\\&#10;x=\frac{21}{6}
6 0
3 years ago
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