3 years ago

Find the domain of the graphed function.

Mathematics

2 answers:

beks73 [17]3 years ago

8 0

B since all x values are less than 0 or are 0

kondor19780726 [428]3 years ago

8 0

The answer is c because it is 10 and that is big so that's y it has that<_

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Select ALL the correct answers.

swat32

5.2 x 10-2 and 5.2 x 10-1

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3 years ago

Read 2 more answers

A number, x, rounded to 2 significant figures is 1300<br>Write down the error interval for x.

nikitadnepr [17]

Answer:

$[1250,1350)$ .

Step-by-step explanation:

It is given that a number, x, rounded to 2 significant figures is 1300.

It is possible if,

1. The value of x is greater than of equal to 1250 and less than or equal to 1300.

i.e., $1250\leq x\leq 1300$ ...(1)

2. The value of x is greater than of equal to 1300 and less than 1350.

i.e., $1300\leq x$ ...(2)

On combining (1) and (2), we get

$1250\leq x < 1350$

1350 is not included in the error interval for x.

Interval notation is $[1250,1350)$ .

Therefore, the error interval for x is $[1250,1350)$ .

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3 years ago

Simplify the cube root in simplest radical form.<br> 9x374<br> Please help

algol [13]

Answer:

D. $xy\sqrt[3]{9y}$

Step-by-step explanation:

$\sqrt[3]{9x^3y^4}$

$\sqrt[3]{9}\sqrt[3]{x^3}\sqrt[3]{y^4}$

The $\sqrt[3]{x^3}$ cancels out to become x:

$\sqrt[3]{9}x\sqrt[3]{y^4}$

Split the $y^4=y*y^3$

$\sqrt[3]{9}x\sqrt[3]{y^3}\sqrt[3]{y^1}$

$\sqrt[3]{y^3} =y$

$xy\sqrt[3]{9} \sqrt[3]{y}$

Put the cube root of y and cube root of 9 together:

$xy\sqrt[3]{9y}$

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3 years ago

Factor: 2x + 2y<br> Show work please

bearhunter [10]

Answer:

2(x + y)

Step-by-step explanation:

You can pull out a 2 from the expression.

So divide 2x by 2 and 2y by 2.

2x/2 = x

2y/2 = y

2(x + y)

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3 years ago

evelyn is going on a hike. she will hike 4 miles in all. so far, she has hiked 1/2 of the total distance. how far has she hiked

lana [24]

Answer:

2 miles

Step-by-step explanation:

1/2 of 4 is 2

Mathematically

1/2 × 4/1

4/2

5 0

3 years ago