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BARSIC [14]
3 years ago
10

A rocket car on the bonneville salt flats is traveling at a rate of 640 miles per hour. How much time would it take for the car

to travel 384 miles at this rate?
Mathematics
2 answers:
Sindrei [870]3 years ago
6 0

Answer:

0.6 hour    or      36 minutes

Step-by-step explanation:

We can use proportion to solve this problem.

640 miles =  1 hour

384 miles   =  x

cross-multiply

640 x   =  384

Divide both-side of the equation by 640

\frac{640x}{640}  =  \frac{384}{640}

(On the left-hand side of the equation 640 at the numerator will cancel-out 640 at the denominator, while on the right-hand side of the equation 384 will be divided by 640)

x  =    \frac{384}{640}

x  = 0.6 hour

or

x = 0.6×60 = 36 minutes

Therefore the time it would take the car to travel 384 miles is 0.6 hour  or  36 minutes  

luda_lava [24]3 years ago
4 0
D = r t 384 = 640 * t 384/640 = t .6 = t .6 of an hour .6 hr * 60min/1 hr = 36 minutes (just in case it needs to be in minutes)
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Find the square of 12 find the square root of 196,324
IRISSAK [1]

Step-by-step explanation:

the square of 12 =12×12 =144

and the square root of 196324 = ✓196324

= 443.084642

5 0
3 years ago
If ex + e⁻¹= 2, then x =..
harkovskaia [24]

Answer:

\rm x = \dfrac{2e - 1}{ {e}^{2} }

Step-by-step explanation:

\rm Solve \:  for \:  x: \\  \rm \longrightarrow ex +  {e}^{ - 1}  = 2 \\  \\   \rm \longrightarrow e x +  \dfrac{1}{e}  = 2 \\  \\  \rm Subtract \:   \dfrac{1}{e} \:  from \:  both  \: sides: \\   \rm \longrightarrow e x  +  \dfrac{1}{e} -  \dfrac{1}{e}  = 2  -  \dfrac{1}{e}  \\  \\   \rm \longrightarrow ex =  \dfrac{2e}{e} -  \dfrac{1}{e}   \\  \\   \rm \longrightarrow ex =  \dfrac{2e - 1}{e}  \\  \\  \rm Divide \:  both  \: sides  \: by  \: e: \\   \rm \longrightarrow  \dfrac{ex}{e}  =  \dfrac{2e - 1}{e \times e}  \\  \\   \rm \longrightarrow x =  \dfrac{2e - 1}{ {e}^{2} }

6 0
3 years ago
Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, trave
USPshnik [31]

Answer:

Julio travel <u>3 hours</u> by biking and <u>4 hours</u> by walking.

Step-by-step explanation:

Given:

Julio started biking to the park traveling 8 mph, after some time the bike got a flat so Julio walked the rest of the way, traveling 7 mph.

If the total trip to the park took 7 hours and it was 52 miles away.

Now, to find the time Julio travel at each speed.

The speed travelled by the bike = 8 mph.

The speed travelled by the walking = 7 mph.

Let the time Julio travel with bike be x.

And the time Julio travel by walking be y.

As, given Julio started biking to the park traveling, after some time the bike got a flat so Julio walked the rest of the way,

Thus, the total time taken:

x+y=7

y=7-x\ \ \ .......(1)

So, the distance travelled by bike:

Speed × time

8\times x=8x

And, the distance travelled by walking:

Speed × time

7\times y=7y

Now, the total distance travelled by Julio:

8x+7y=52

Substituting the value of x from equation (1) we get:

8x+7(7-x)=52

8x+49-7x=52\\\\x+49=52

<em>Subtracting both sides by 49 we get:</em>

x=3.

<em>The time Julio travelled with bike = 3 hours.</em>

Now, to get the time Julio travelled by walking by substituting the value of x:

y=7-x\\\\y=7-3\\\\y=4\ hours.

<em>The time Julio travelled by walking = 4 hours.</em>

Therefore, Julio travel 3 hours by biking and 4 hours by walking.

7 0
3 years ago
What would the total area be??
timurjin [86]

Answer:

1,560,000 mm²

Step-by-step explanation:

A= \frac{(1600*600)}{2} This would make shape A's area <u>480,000</u>.

B= \frac{(600*600)}{2} This would make shape B's area <u>180,000</u>.

C= \frac{(1000*600)}{2} This would make shape C's area <u>300,000</u>.

D= 1000×600 This wouls make D's area <u>600,000</u>.

Now you add up all of the areas;

480,000+180,000+300,000+600,000= 1,560,000 mm²

6 0
3 years ago
Read 2 more answers
The quality-control manager at a compact flourescent light bulb factory wants to test the claim that the mean life of a large sh
MAXImum [283]

Answer:

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. CI [6583.336 ,6816.336]

d.  The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

Step-by-step explanation:

Population mean = u= 6500 hours.

Population standard deviation = σ=500 hours.

Sample size =n= 50

Sample mean =x`=  6,700 hours

Sample standard deviation=s=  600 hours.

Critical values, where P(Z > Z) =∝ and P(t >) =∝

Z(0.10)=1.282  

Z(0.05)=1.645  

Z(0.025)=1.960  

t(0.01)(49)= 1.299

t(0.05)= 1.677  

t(0.025,49)=2.010

Let the null and alternate hypotheses be

H0: u = 6500 against the claim Ha: u ≠ 6500

Applying Z test

Z= x`- u/ s/√n

z= 6700-6500/500/√50

Z= 200/70.7113

z= 2.82=2.82

Applying  t test

t= x`- u /s/√n

t= 6700-6500/600/√50

t= 2.82

a. At the 0.05 level of significance,  there is evidence that the mean life is different from 6,500 hours.

Yes we reject H0  for z- test as it falls in the critical region,at the 0.05 level of significance, z=2.82 > z∝=1.645

For t test  we reject H0   as it falls in the critical region,at the 0.05 level of significance, t=2.82 > t∝=1.677 with n-1 = 50-1 = 49 degrees of freedom.

b. The p value= ≈ 0.00480 for z- test which is less than 0.05 and H0 is rejected .

The p value= 0.006913 for t- test which is less than 0.05 and H0 is rejected for 49 degrees of freedom.

c. The 95 % confidence interval of the population mean life is estimated by

x` ±  z∝/2  (σ/√n )

6700± 1.645 (500/√50)

6700±116.336

6583.336 ,6816.336

d. The range of CI [6583.336 ,6816.336] tells that the cfls having a different mean life lie in this range.

6 0
3 years ago
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