Answer:
16mm
Step-by-step explanation:
Just do 40 * 2/5 = 80/5 = 16mm
Q= 31/1 I might be wrong but I’m not sure
Answer:
![cos^2\theta + sin^2\theta = 1](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%2B%20sin%5E2%5Ctheta%20%3D%201)
Step-by-step explanation:
Given
![(\frac{b}{r})^2 + (\frac{a}{r})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2)
Required
Use the expression to prove a trigonometry identity
The given expression is not complete until it is written as:
![(\frac{b}{r})^2 + (\frac{a}{r})^2 = (\frac{r}{r})^2](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2%20%20%3D%20%28%5Cfrac%7Br%7D%7Br%7D%29%5E2)
Going by the Pythagoras theorem, we can assume the following.
- a = Opposite
- b = Adjacent
- r = Hypothenuse
So, we have:
![Sin\theta = \frac{a}{r}](https://tex.z-dn.net/?f=Sin%5Ctheta%20%3D%20%5Cfrac%7Ba%7D%7Br%7D)
![Cos\theta = \frac{b}{r}](https://tex.z-dn.net/?f=Cos%5Ctheta%20%3D%20%5Cfrac%7Bb%7D%7Br%7D)
Having said that:
The expression can be further simplified as:
![(\frac{b}{r})^2 + (\frac{a}{r})^2 = 1](https://tex.z-dn.net/?f=%28%5Cfrac%7Bb%7D%7Br%7D%29%5E2%20%20%2B%20%28%5Cfrac%7Ba%7D%7Br%7D%29%5E2%20%20%3D%201)
Substitute values for sin and cos
becomes
![cos^2\theta + sin^2\theta = 1](https://tex.z-dn.net/?f=cos%5E2%5Ctheta%20%2B%20sin%5E2%5Ctheta%20%3D%201)
It would be -56, just multiply as normal