Technology is addicting and distracting, just take personal experience. Have you ever had a time when you were on the computer, on the phone, playing games, watching TV, etc. and time flew by? You were procrastinating and should have been doing something else? Were you ever multitasking and paid more attention to technology than what you should be doing? If so, then you have your answer, and from your own experience as well.
Assuming the data was encrypted with YOUR public key, you'll need YOUR private key to decrypt it. That's answer e.
a and b are not solutions by themselves, of course you need to use the decryption algorithm, but a key goes with it.
c would be about symmetric encryption, but this is asymmetric, so different keys are used for encryption and decryption
d is possible, but it would mean anyone can decrypt it (after all the key is public), so then there's no point in encrypting it in the first place.
So e is the only logical answer.
Answer:
Explanation:
#include <iostream>
using namespace std;
int costdays(int);
int costhrs(int,int);
int main()
{
int dd,hh,mm,tmph,tmpd,tmpm=0;
int pcost,mcost=0;
cout<<"Enter Parking time" << endl;
cout<<"Hours: ";
cin>>hh;
cout<<"Minutes: ";
cin>>mm;
if (mm>60)
{
tmph=mm/60;
hh+=tmph;
mm-=(tmph*60);
}
if (hh>24)
{
tmpd=hh/24;
dd+=tmpd;
hh-=(tmpd*24);
}
if ((hh>4)&&(mm>0))
{
pcost+=costdays(1);
}
else
{
mcost=costhrs(hh,mm);
}
cout<<"Total time: ";
if (dd>0)
{
cout<<dd<<"days ";
pcost+=costdays(dd);
}
pcost+=mcost;
cout<<hh<<"h "<<mm<<"mins"<<endl;
cout<<"Total Cost :"<<pcost<<"Won";
return 0;
}
int costdays(int dd)
{
return(dd*25000);
}
int costhrs(int hh,int mm)
{
int tmpm, tmp=0;
tmp=(hh*6)*1000;
tmp+=(mm/10)*1000;
tmpm=mm-((mm/10)*10);
if (tmpm>0)
{
tmp+=1000;
}
return(tmp);
}
Hi!
When ever we start or restart any device we may hold - this process is called <em>booting. </em>
Hopefully, this helps! =)
