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3 years ago

I NEED THIS ASAP Are two regular hexagons always congruent? Explain your answer

2 answers:

8 0

The two regular hexagons could have different side lengths, so they will not necessarily always be congruent, but they will always be similar.

Savatey [412]3 years ago

3 0

They come in many different sizes so they are not always congruent but they are always similar

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Rosa earns $120 per week tutoring math. Each week, she puts $36 from her paycheck in her bank account to save for college. Rosa

natita [175]

Answer:

36/120 x 100

= 30%

..............

3 0

2 years ago

What is the minimum value of 2x + 2y in the feasible region?

Liono4ka [1.6K]

Find and graph the feasible region for the following constraints: x + y < 5. 2x + y > 4 ... y = 10/3. x = 30/3 - 10/3 = 20/3. Intersects at (20/3, 10/3). -x + 2y = 0. x - 2y = 0.

6 0

3 years ago

3/4 of the weight of a bunch of grapes is equivalent to 3/5 of the weight of a papaya. If the grapes way (X +28) pounds what is

Margaret [11]

Let p = weight of papaya and g = weight of grapes.

Then (3/4)g = (3/5)p. Since the weight of grapes is x + 28,

(3/4)(x + 28) = (3/5)p. We must solve for x. To do this, mult. both sides by (5/3):

(5/3)(3/4)(x+28) = (5/3)(3/5)p

Then p = (15/9)(x+28), or (after reduction), p = (5/3)(x+28).

4 0

3 years ago

assume that when adults with smartphones are randomly selected 15 use them in meetings or classes if 15 adult smartphones are ra

Tanzania [10]

Answer:

The probability that at least 4 of them use their smartphones is 0.1773.

Step-by-step explanation:

We are given that when adults with smartphones are randomly selected 15% use them in meetings or classes.

Also, 15 adult smartphones are randomly selected.

Let X = Number of adults who use their smartphones

The above situation can be represented through the binomial distribution;

$P(X = r) = \binom{n}{r}\times p^{r} \times (1-p)^{n-r} ; n = 0,1,2,3,.......$

where, n = number of trials (samples) taken = 15 adult smartphones

r = number of success = at least 4

p = probability of success which in our question is the % of adults

who use them in meetings or classes, i.e. 15%.

So, X ~ Binom(n = 15, p = 0.15)

Now, the probability that at least 4 of them use their smartphones is given by = P(X $\geq$ 4)

P(X $\geq$ 4) = 1 - P(X = 0) - P(X = 1) - P(X = 2) - P(X = 3)

= $1- \binom{15}{0}\times 0.15^{0} \times (1-0.15)^{15-0}-\binom{15}{1}\times 0.15^{1} \times (1-0.15)^{15-1}-\binom{15}{2}\times 0.15^{2} \times (1-0.15)^{15-2}-\binom{15}{3}\times 0.15^{3} \times (1-0.15)^{15-3}$

= $1- (1\times 1\times 0.85^{15})-(15\times 0.15^{1} \times 0.85^{14})-(105 \times 0.15^{2} \times 0.85^{13})-(455 \times 0.15^{3} \times 0.85^{12})$

= 0.1773

3 0

3 years ago

A computer fan's speed rises as the computer heats up. Based on the table, what is MOST LIKELY the fan's speed at 7 minutes?

kumpel [21]

Answer:

2,800

Step-by-step explanation:

Because they are adding 700 each time.

7 0

2 years ago