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blsea [12.9K]
3 years ago
5

How does water’s high specific heat capacity affect large lakes?

Chemistry
2 answers:
soldi70 [24.7K]3 years ago
7 0
<h2>Answer:</h2>

The water has higher specific heat capacity which affects the lakes largely in such way that the water in a lake changes temperature slowly.

<h2>Explanation:</h2>

Evaporation is a process of liquid changing its state to gaseous state at any temperature. Water has high specific heat due to the presence of strong hydrogen bonds. Due to which it requires heat in huge amount to raise the water (in large quantity) temperature.

Thus, the molecules will be unable to gain much kinetic energy that result in changing the temperature very slowly.

Brums [2.3K]3 years ago
4 0

Answer:

D. The water in a lake changes temperature slowly.

Explanation:

for plato users

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barxatty [35]

Answer:

87.5

Explanation:

3.5 L to g would be 3500

3500*2.5%= 87.5 g

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2 years ago
It requires work to _____. A. stretch a spring only B. compress a spring only C. stretch or compress a spring
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C.

Explanation:

It requires work to stretch or compress a spring.

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4 years ago
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If there is 25.0 L of gas at a temperature of 350C what is the temperature if the volume increases to 75.0L?
Zielflug [23.3K]

Answer:

The new temperature is 1596 C.

Explanation:

Charles's Law indicates that for a given sum of gas at constant pressure, as the temperature increases, the volume of the gas increases, and as the temperature decreases, the volume of the gas decreases.

Statistically, Charles's law is a law that says that when the amount of gas and pressure are kept constant, the ratio that exists between the volume and the temperature will always have the same value:

\frac{V}{T}=k

Being an initial state 1 and a final state 2, it is fulfilled:

\frac{V1}{T1}=\frac{V2}{T2}

In this case:

  • V1= 25 L
  • T1= 350 C= 623 K (being 0 C= 273 K)
  • V2= 75 L
  • T2= ?

Replacing:

\frac{25 L}{623 K} =\frac{75 L}{T2}

Solving:

T2*\frac{25 L}{623 K} =75 L

T2=75 L*\frac{623 K}{25 L}

T2= 1869 K= 1596 C

<u><em>The new temperature is 1596 C.</em></u>

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3 years ago
Which of these is an example of solar energy?
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4 years ago
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Water is flowing in a pipe with a mass flow rate of 100.0 lb/h (M water H,O=18.016). What is the (i) Molar flow rate of H20 (gmo
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Answer:

i) 0,7 molH20/s

ii)11,2 g O/s

iii)1,4 g H/s

Explanation:

i) To find the molar flow rate of water, we just convert the mass of water to moles of water using its molecular weight(g/mol) and changing to the proper units (lb to grames and hours to seconds):

100 \frac{lb}{h}*\frac{453,5g}{1 lb}*\frac{1molH20}{18,016g}*\frac{1h}{3600s}=0,7\frac{molH20}{s}

ii) Now we just consider the oxygen in the water stream (for 1 mole of water there is 1 mole of oxygen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{1molO}{1molH20}*\frac{16gr}{1molO}*\frac{1h}{3600s}=11,2\frac{gO}{s}

iii)Just considering the hydrogen in the stream (for 1 mole of water there is 2 moles of hydrogen):

100\frac{lb}{h} *\frac{453,5g}{1lb}*\frac{1 molH20}{18,016g}*\frac{2molH}{1molH20}*\frac{1gr}{1molH}*\frac{1h}{3600s}=1,4\frac{gH}{s}

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3 years ago
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