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Arturiano [62]
3 years ago
10

How may this stored water be renewed ?

Chemistry
2 answers:
inna [77]3 years ago
5 0
It has to be renewed in a filter
Montano1993 [528]3 years ago
3 0
The water may stored water in a filter
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What is the basis for the classification of changes in matter into physical and chemical changes quizlet
laiz [17]

Explanation:

The basis for classifying changes in matter into physical and chemical change is to see if a material is altered after going through a process.

In a physical change only the state of matter is usually altered especially its form or shape.

Chemical change alters a substance by producing new kinds that are totally different from it.

  • In  a chemical change, new kinds of matter are usually formed.
  • Such changes are usually irreversible.
  • Change of state is a reversible process.

learn more:

Chemical change brainly.com/question/9388643

#learnwithBrainly

6 0
3 years ago
If you start with 13 mole H2O and 50 grams of O2 what is the percent yield of H202 if 100 grams of H202 is actually made?
dmitriy555 [2]

Answer:

94.1 %

Explanation:

We firstly determine the equation:

2H₂O + O₂ →  2H₂O₂

2 moles of water react to 1 mol of oxygen in order to produce 2 moles of oxygen peroxide.

We convert the mass of oxygen to moles:50 g . 1mol /32g = 1.56 mol

Certainly oxygen is the limiting reactant.

2 moles of water react to 1 mol of oxygen.

13 moles of water may react to 13/2 = 6.5 moles. (And we only have 1.56)

As we determine the limiting reactant we continue to the products:

1 mol of O₂ can produce 2 moles of H₂O₂

Then 1.56 moles of O₂ will produce (1.56 . 2) = 3.125 moles

We convert the moles to mass: 3.125 mol . 34 g/mol= 106.25 g

That's the 100% yield or it can be called theoretical yield.

Percent yield = (Yield produced / Theoretical yield) . 100

(100g / 106.25 g) . 100 = 94.1 %

3 0
3 years ago
131i has a half-life of 8.04 days. assuming you start with a 1.53 mg sample of 131i, how many mg will remain after 13.0 days ___
inn [45]
For this problem we can use half-life formula and radioactive decay formula.

Half-life formula,
t1/2 = ln 2 / λ

where, t1/2 is half-life and λ is radioactive decay constant.
t1/2 = 8.04 days

Hence,         
8.04 days    = ln 2 / λ                         
λ   = ln 2 / 8.04 days

Radioactive decay law,
Nt = No e∧(-λt)

where, Nt is amount of compound at t time, No is amount of compound at  t = 0 time, t is time taken to decay and λ is radioactive decay constant.

Nt = ?
No = 1.53 mg
λ   = ln 2 / 8.04 days = 0.693 / 8.04 days
t    = 13.0 days 

By substituting,
Nt = 1.53 mg e∧((-0.693/8.04 days) x 13.0 days))
Nt = 0.4989 mg = 0.0.499 mg

Hence, mass of remaining sample after 13.0 days = 0.499 mg

The answer is "e"

8 0
3 years ago
Calculate the mass of 4.55x1024 molecules of sucrose
maxonik [38]

Answer:

2584 g

Explanation:

The molecular formula for sucrose is C₁₂H₂₂O₁₁, which means its molar mass is 342.3 g/mol.

First we<u> convert molecules into moles</u> by using <em>Avogadro's number</em>:

  • 4.55x10²⁴ molecules ÷ 6.023x10²³ mol/molecules = 7.55 mol

Now we <u>convert moles of sucrose into grams</u>, using its<em> molar mass</em>:

  • 7.55 mol * 342.3 g/mol = 2584 g
7 0
3 years ago
Which statement about biogeochemical cycles is true?
Marianna [84]
The answer would be C!!!!!!!!!!!!!!!!!!
4 0
3 years ago
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