The one that doesnt belong is the 3 one
All we need to do is to divide August and September rainfall measurements into two equal halves and then substract 0.6 from one of them and add 0.6 to the other one.
6.2 ÷ 2 = 3.1
3.1 - 0.6 = 2.5
3.1 + 0.6 = 3.7
It's said that in August there was 0.6 inch more rainfall, so the bigger value (3.7 inches) is for August and the smaller value (2.5 inches) is for September.
Let the origin of the coordinate system be the position of ship B at noon. Then the distance between the ships as a function of t (in hours) is
.. d = √((30 +23t)² +(17t)²)
.. = √(818t² +1380t +900)
The rate of change of distance with respect to time is
.. d' = (1/2)(2*818*t +1380)/√(818t² +1380t +900)
.. = (818t +690)/√(818t² +1380t +900)
At t=4, this is
.. d' = (818*4 +690)/√(818*16 +1380*4 +900)
.. = 3962/√19508
.. ≈ 28.37 . . . . . knots
The distance between the ships is increasing at about 28.37 knots at 4 pm.
Answer:
The Blue box is your answer
Step-by-step explanation:
Multiply 4, 8, and 7 and you get 224. The problem states that it should not be over 250, and 224 is not over 250. So the blue box is your best go.