The question here is how long does it take for a falling
person to reach the 90% of this terminal velocity. The computation is:
The terminal velocity vt fulfills v'=0. Therefore vt=g/c,
and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the
differential equation shows that the time needed to reach velocity v is
<span>To solve it, use the quadratic formula with (½)(-32.174 ft/s²) = a, 38 ft/s = b, and 30 ft = c. There are two answers; the only positive answer is t = 2.986 s </span>
Set up a proportion. 2/5 = x/40 to solve the equation first cross multiply. x*5=40*2 x*5=80 now divide both sides by 5, 80 divided by 5 is equal to 16. so the number of girls in the computer lab is 16.
