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nadya68 [22]
3 years ago
11

The terminal velocity of a person falling through air is about 100Km/hr. The acceleration due to gravity is 10ms−2. Use this inf

ormation to find out what C is in the equation v′=C(gC−v), where g is the acceleration due to gravity and v is the velocity.
Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
8 0

The question here is how long does it take for a falling person to reach the 90% of this terminal velocity. The computation is:

The terminal velocity vt fulfills v'=0. Therefore vt=g/c, and so c=g/vt = 10/(100*1000/3600) = 36,000/100,000... /s. Incorporating the differential equation shows that the time needed to reach velocity v is 

t= ln [g / (g-c*v)] / c. 

With v=.9 vt =.9 g/c,

t = ln [10] /c = 6.4 sec.

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The rate of change for a variables based on another variable is known as the slope.

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Compute the rate of change for the money earned, measured as dollars per delivery, between 2 and 4 deliveries as follows:

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The rate of change for the money earned, measured as dollars per delivery, between 6 and 8 deliveries is $2.

Thus, the rate of change is the same between the two time intervals.

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