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2 years ago

FIRST TO ANSWER GET BRAINLEST.

Mathematics

1 answer:

Lostsunrise [7]2 years ago

3 0

Answer:

I believe the answer is B sorry if I'm wrong

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Use the drawing tools to form the correct answer on the provided graph. Graph the solution to the following linear inequality in

JulsSmile [24]

Answer:

solve for x first and then y

Step-by-step explanation:

once you know what x is than y , ur answer will equall out

6 0

3 years ago

Emanuel and Zachary are trying to reduce the amount of television they watch. For every hour they watch television, they have to

hichkok12 [17]

Answer:

You can buy 6 tickets.

Step-by-step explanation:

21.8 + 26.6 = 48.4

48.4 x 2.50 = 121

121 / 17.50 = 6.914

Since we can't round here because it's items you're buying, we round down to the nearest flat number, which in this case is 6.

8 0

2 years ago

Which statement best reflects the solution(s) of the equation?

Inessa [10]

x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Step-by-step explanation:

We need to solve the equation $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ and find values of x.

Solving:

Find the LCM of denominators x-1,x and x-1. The LCM is x(x-1)

Multiply the entire equation with x(x-1)

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}\\\frac{1}{x-1}*x(x-1)+\frac{2}{x}*x(x-1)=\frac{x}{x-1}*x(x-1)\\Cancelling\,\,out\,\,the\,\,same\,\,terms:\\x+2(x-1)=x^2\\x+2x-2=x^2\\3x-2=x^2\\x^2-3x+2=0$

Now, factoring the term:

$x^2-2x-x+2=0\\x(x-2)-1(x-2)=0\\(x-1)(x-2)=0\\x-1=0\,\,and\,\, x-2=0\\x=1\,\,and\,\, x=2$

The values of x are x=1 and x=2

Checking for extraneous roots:

Extraneous roots: The root that is the solution of the equation but when we put it in the equation the answer turns out not to be right.

If we put x=1 in the equation, $\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$ the denominator becomes zero i.e

$\frac{1}{1-1}+\frac{2}{1}=\frac{1}{1-1}\\\frac{1}{0}+2=\frac{1}{0}$

which is not correct as in fraction anything divided by zero is undefined. So, x=1 is an extraneous solution.

If we put x=2 in the equation,

$\frac{1}{x-1}+\frac{2}{x}=\frac{x}{x-1}$

$\frac{1}{2-1}+\frac{2}{2}=\frac{2}{2-1}\\\frac{1}{1}+1=\frac{2}{1}\\1+1=2\\2=2$

So, x=2 is only solution while x=1 is extraneous solution

Option C is correct.

Keywords: Solving Equations and checking extraneous solution

Learn more about Solving Equations and checking extraneous solution at:

#learnwithBrainly

5 0

3 years ago

Which statement is true about the equations 3x + 4y = 12 and ¿-X- = = 1?

jarptica [38.1K]

Answer:

cfhjytgfhe5tgnbg5etjgnbg345jthgbyu6jtngfyu6jyh

Step-by-step explanation:

4 0

3 years ago

What is the range of function g? <br>

vlada-n [284]

Using it's concept, the range of function g is given by:

B. $\{y|y \in \mathbb{R}, y \neq -4, -3\}$

<h3>What is the range of a function?</h3>

The range of a function is the set that contains all possible output values for the function. In a graph, it is the values of y.

In this graph, y assumes all values except y = -3 and y = -4, hence the range is given by:

B. $\{y|y \in \mathbb{R}, y \neq -4, -3\}$

More can be learned about the range of a function at brainly.com/question/10891721

#SPJ1

4 0

2 years ago