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WINSTONCH [101]
3 years ago
9

What is the least common multiple of 2 and 9

Mathematics
2 answers:
Mkey [24]3 years ago
7 0

Answer:

1

Step-by-step explanation:

numbers that can be multiplied and resulted into these numbers.

harina [27]3 years ago
5 0

Answer:

18

hope this helps

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[7.07] Choose the correct product of (6x + 2)2.
Elodia [21]
Answer:
36x^2 + 24x + 4

Explanation:
The perfect square has the following general formula:
(a + b)^2 = a^2 + 2ab + b^2

Now, we will expand the given perfect square based on the above general formula:
(6x + 2)^2 = (6x)^2 + 2(6x*2) + (2)^2
                 = 36x^2 + 24x + 4

Hope this helps :)
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Mrs. Thomas wants to put a table in the corner of a room. She considers the measurements of these tables. Table 1 length: 1.5 fe
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Determine whether the relationship is a function. Complete the explanation.
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You Have 320 shares of stock in a film making company and 460 shares of stock in an electronics company. The film making company
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7 0
3 years ago
In how many ways can 100 identical chairs be distributed to five different classrooms if the two largest rooms together receive
Eva8 [605]

Answer:

There are 67626 ways of distributing the chairs.

Step-by-step explanation:

This is a combinatorial problem of balls and sticks. In order to represent a way of distributing n identical chairs to k classrooms we can align n balls and k-1 sticks. The first classroom will receive as many chairs as the amount of balls before the first stick. The second one will receive as many chairs as the amount of balls between the first and the second stick, the third classroom will receive the amount between the second and third stick and so on (if 2 sticks are one next to the other, then the respective classroom receives 0 chairs).

The total amount of ways to distribute n chairs to k classrooms as a result, is the total amount of ways to put k-1 sticks and n balls in a line. This can be represented by picking k-1 places for the sticks from n+k-1 places available; thus the cardinality will be the combinatorial number of n+k-1 with k-1, {n+k-1 \choose k-1} .

For the 2 largest classrooms we distribute n = 50 chairs. Here k = 2, thus the total amount of ways to distribute them is {50+2-1 \choose 2-1} = 51 .

For the 3 remaining classrooms (k=3) we need to distribute the remaining 50 chairs, here we have {50+3-1 \choose 3-1} = {52 \choose 2} = 1326 ways of making the distribution.

As a result, the total amount of possibilities for the chairs to be distributed is 51*1326 = 67626.

7 0
3 years ago
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