6x+4y=42 -3x+3y=-6 by elimination
2 answers:
Answer:
x=5, y=2
Step-by-step explanation:
To solve this system, we need to find x and y. First, let's find x. In the first equation (6x+4y=42), subtract 4y on both sides to isolate 6x. This will result in 6x=42-4y. Divide by 6 on both sides to isolate x and get x=7-y. Now we know what x equals. Go to the second equation ad plug this into it. So instead of -3x+3y=-6, you'll have -3(7-
y)+3y=-6. Use the distributive property to get -21+2y+3y=-6. Add 2y and 3y to get -21+5y=-6. Add 21 to both sides to isolate 5y and get 5y=15. Divide by 5 on both sides to isolate y and get y=3. Now that we know that y=3, we can plug this back into the equation that was bolded above so that we can find x, so we'll have x=7-
(3) since y=3, and we'll get x=7-
, or x=7-2, or x=5.
x=5
y=2
Answer: (5, 3)
Step-by-step explanation:
Solve by Addition/Elimination
6x + 4y = 42 −3x + 3y = −6
Multiply each equation by the value that makes the coefficients of x opposite.
6x + 4y = 42
(2) ⋅ (−3x + 3y) = (2) (−6)
Simplify (2) ⋅ (−3x + 3y).
6x + 4y = 42
−6x + 6y = (2) (−6)
Multiply 2 by −6. 6x + 4y = 42
−6x + 6y = −12
Add the two equations together to e liminate x from the system.
6x + 4y = 42
<u>±6x + 6y = −12 </u>
1 0y= 30
Divide each term in 10y = 30 by 10.
<u> 10</u>y = <u>30</u>
10 10
Cancel the common factor of 10.
y = 30/10
Divide 30 by 10.
y = 3
Substitute the value found for y into one of the original equations, then solve for x.
Substitute the value found for y into one of the original equations to solve for x. 6x + 4 (3) = 42
Multiply 4 by 3.
6x + 12 = 42
Move all terms not containing x to the right side of the equation.
6x = 30
Divide each term by 6 and simplify.
x = 5
The solution to the independent system of equations can be represented as a point.
(5, 3)
The result can be shown in multiple forms.
Point Form:
(5, 3)
Equation Form:
x = 5, y = 3
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