Question

A game involves correctly choosing the 5 correct numbers from 1 through 18 that are randomly drawn. What is the probability that a person wins the game, if they enter a) once? b) 7 times with a different choice each time?

Answer 1

Answer:

$=\frac{1}{8568}\ = .00011\\\ =\frac{7}{8568} = .00081$

Step-by-step explanation:

$5/18\cdot \:4/17\cdot \:3/16\cdot \:2/15\cdot \:1/14=\frac{1}{8568}$