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2 years ago

X>= -5 and y>= -3 draw a graph with the following domain and range restrictions.

Mathematics

1 answer:

IRISSAK [1]2 years ago

3 0

Answer:(-5,-3) -5 to left -3 down

Step-by-step explanation:

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Dan is watching the birds in his backyard. Of the birds he watches, 9 of them, or 45%, are sparrows. How may birds are in his ba

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Answer:

Step-by-step explanation:45 divided by 9 is 5

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2 years ago

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Solve the following and explain your steps. Leave your answer in base-exponent form. (3^-2*4^-5*5^0)^-3*(4^-4/3^3)*3^3 please st

Naily [24]

Answer:

$\boxed{2^{\frac{802}{27}} \cdot 3^9}$

Step-by-step explanation:

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$(3^{-2} \cdot 4^{-5} \cdot 5^0)^{-3} \cdot (4^{-\frac{4}{3^3} })\cdot 3^3$

Note that

$\boxed{a^{-b} = \dfrac{1}{a^b}, a\neq 0 }$

The denominator can't be 0 because it would be undefined.

So, we can solve the expression inside both parentheses.

$\left(\dfrac{1}{3^2} \cdot \dfrac{1}{4^5} \cdot 5^0 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{3^3} } }\right)\cdot 3^3$

Also,

$\boxed{a^{0} = 1, a\neq 0 }$

$\left(\dfrac{1}{9} \cdot \dfrac{1}{1024} \cdot 1 \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

Note

$\boxed{\dfrac{1}{a} \cdot \dfrac{1}{b}= \frac{1}{ab} , a, b \neq 0}$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{1}{4^{\frac{4}{27} } }\right)\cdot 27$

$\left(\dfrac{1}{9216} \right)^{-3} \cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left( \dfrac{1}{\left(\dfrac{1}{9216}\right)^3} \right)\cdot \left(\dfrac{27}{4^{\frac{4}{27} } }\right)$

Note

$\boxed{\dfrac{1}{\dfrac{1}{a} } = a}$

$9216^3\cdot \left(\dfrac{27}{4^{\frac{4}{9} } }\right)$

$\left(\dfrac{ 9216^3\cdot 27}{4^{\frac{4}{27} } }\right)$

Once

$9216=2^{10}\cdot 3^2 \implies 9216^3=2^{30}\cdot 3^6$

$\boxed{(a \cdot b)^n=a^n \cdot b^n}$

And

$4^{\frac{4}{27}} = 2^{\frac{8}{27}$

We have

$\left(\dfrac{ 2^{30} \cdot 3^6\cdot 27}{2^{\frac{8}{27} } }\right)$

Also, once

$\boxed{\dfrac{c^a}{c^b}=c^{a-b}}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27$

$30-\dfrac{8}{27} = \dfrac{30 \cdot 27}{27}-\dfrac{8}{27} =\dfrac{802}{27}$

$2^{30-\frac{8}{27}} \cdot 3^6\cdot 27 = 2^{\frac{802}{27}} \cdot 3^6 \cdot 3^3$

$2^{\frac{802}{27}} \cdot 3^9$

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2 years ago

The basketball team is playing in the championship game and wants to take a bus filled with family and friends to cheer for the

sergij07 [2.7K]

Answer:

Maximum number of people is 35

Step-by-step explanation:

With a total of $160 you have to pay for the bus and all the people. The bus cost $90 so you subtract that from the 160 because you bought (or rented) the bus. Then you have $70 left to pay for everyone's tickets. If each ticket is $2 then you can buy 35 tickets in total because 70 divided by 2 = 35.

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2 years ago

I have 1 hundreds, 4 ones, 2 tens, and 1 tenths. What number am I?

DaniilM [7]

Since it reads 1 hundreds, that means 100. 4 ones mean 4 * 1, which is 4. 2 tens means 2 * 10, which is 20. Add those together and you get 124. Where it reads "1 tenth", that means 0.1
Therefore, the number is 124.1

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3 years ago

NEED HELP, LIMITED TIME, HURRY

11111nata11111 [884]

Answer:

Step-by-step explanation:

here you go!

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3 years ago

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