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3 years ago

15

Angle ABC is congruent to which angle?

1 answer:

Llana [10]3 years ago

6 0

Answer:

CBA=MNP

Step-by-step explanation:

Side NP=CB

Side NM=AB

then the angles between those sides are equal

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Find the distance between a point (6, 9) and a horizontal line at y = 5. A) 4 B) 11 C) 15 D) 14

xxTIMURxx [149]

Answer: A.) 4

Step-by-step explanation:

Given the following:

Horizontal line y = 5

Point (6, 9)

Distance between point (6, 9) and horizontal line y = 5

For point (6,9) ; x1 = 6, y1 = 9

Horizontal line : y = 5

Hence, distance between the two points will be the difference between the the y values :

y1 - y = 9 - 5 = 4

Hence, the distance between a point (6, 9) and a horizontal line at y = 5 is 4

8 0

3 years ago

The expression (secx + tanx)2 is the same as _____.

trapecia [35]

<u>Answer:</u>

The expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

<u>Solution:</u>

From question, given that $\bold{(\sec x+\tan x)^{2}}$

By using the trigonometric identity $(a + b)^{2} = a^{2} + 2ab + b^{2}$ the above equation becomes,

$(\sec x+\tan x)^{2} = \sec ^{2} x+2 \sec x \tan x+\tan ^{2} x$

We know that $\sec x=\frac{1}{\cos x} ; \tan x=\frac{\sin x}{\cos x}$

$(\sec x+\tan x)^{2}=\frac{1}{\cos ^{2} x}+2 \frac{1}{\cos x} \frac{\sin x}{\cos x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

$=\frac{1}{\cos ^{2} x}+\frac{2 \sin x}{\cos ^{2} x}+\frac{\sin ^{2} x}{\cos ^{2} x}$

On simplication we get

$=\frac{1+2 \sin x+\sin ^{2} x}{\cos ^{2} x}$

By using the trigonometric identity $\cos ^{2} x=1-\sin ^{2} x$ ,the above equation becomes

$=\frac{1+2 \sin x+\sin ^{2} x}{1-\sin ^{2} x}$

By using the trigonometric identity $(a+b)^{2}=a^{2}+2ab+b^{2}$

we get $1+2 \sin x+\sin ^{2} x=(1+\sin x)^{2}$

$=\frac{(1+\sin x)^{2}}{1-\sin ^{2} x}$

$=\frac{(1+\sin x)(1+\sin x)}{1-\sin ^{2} x}$

By using the trigonometric identity $a^{2}-b^{2}=(a+b)(a-b)$ we get $1-\sin ^{2} x=(1+\sin x)(1-\sin x)$

$=\frac{(1+\sin x)(1+\sin x)}{(1+\sin x)(1-\sin x)}$

$= \frac{1+\sin x}{1-\sin x}$

Hence the expression $\bold{(\sec x+\tan x)^{2} \text { is same as } \frac{1+\sin x}{1-\sin x}}$

8 0

3 years ago

A trampoline bounce place charges a $10 entry fee and an hourly rate for bouncing on their trampolines. Which equation represent

lisov135 [29]

The answer is A. C=10h

8 0

3 years ago

What is the multiplicative inverse of c d ? Explain how a number is related to its multiplicative inverse.

nikklg [1K]

Answer:

$\frac{d}{c}$

Step-by-step explanation:

If a be a real number,

Then the product of a and its multiplicative inverse is equal to the multiplicative identity, i.e. 1,

∵ $a\times \frac{1}{a}=1$

Thus, the multiplicative inverse of a is $\frac{1}{a}$

By comparing it,

We found that,

The multiplicative inverse of $\frac{c}{d}$ is $\frac{1}{c/d}$

i.e. $\frac{d}{c}$

6 0

3 years ago

Determine wether the graphs of y=3x+5 and -y=-3x-13 are parallel, perpendicular, coincident, or none of these

Yanka [14]

They are parallel, use desmos graphing calculator (it is online) and it will show you that the functions are parallel

7 0

3 years ago